Theorem 7. Every element of R has an additive inverse. More specificially, if x = [(a,)], then -æ = [(-a;)]. Proof. Let æ E R. Write a as [(a;)] where (a;) is Cauchy in Q. By Lemma 6 the sequence (-a;) is also Cauchy, so y = [(-a;)] is a real number. We leave it to the reader to show that y is the additive inverse of x. SO
Theorem 7. Every element of R has an additive inverse. More specificially, if x = [(a,)], then -æ = [(-a;)]. Proof. Let æ E R. Write a as [(a;)] where (a;) is Cauchy in Q. By Lemma 6 the sequence (-a;) is also Cauchy, so y = [(-a;)] is a real number. We leave it to the reader to show that y is the additive inverse of x. SO
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Complete the proof for Theorem 7.

Transcribed Image Text:Exercise 4. Complete the proof of the above theorem.
![Theorem 7. Every element of R has an additive inverse. More specificially,
if a = [(a;)], then -x = [(-a;)].
Proof. Let a E R. Write r as [(a;)] where (a;) is Cauchy in Q. By Lemma 6
the sequence (-a;) is also Cauchy, so y = [(-a;)] is a real number. We leave
it to the reader to show that y is the additive inverse of x.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F946be153-534b-47e9-b2ae-1271a90bac9b%2Ffb95a9f1-604d-4152-9a33-e2adcd3ec4a8%2Fqjxlkq_processed.png&w=3840&q=75)
Transcribed Image Text:Theorem 7. Every element of R has an additive inverse. More specificially,
if a = [(a;)], then -x = [(-a;)].
Proof. Let a E R. Write r as [(a;)] where (a;) is Cauchy in Q. By Lemma 6
the sequence (-a;) is also Cauchy, so y = [(-a;)] is a real number. We leave
it to the reader to show that y is the additive inverse of x.
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