Implement the following function, in which a while loop is used to keep taking out two minimum elements from the tree, by calling heapq.heappop (), andthen merging them to a new node, and lastly inserting the new node back to tree.Note that:• The new node does not need to have a self.char attribute, so you can let it be NoneRemember to specify the left and right children nodes correctly for the new node.The function changes tree in place. So, you don't need to return treeIn [ ]: def merge_nodes (tree):### START YOUR CODE ###while(len(tree)>1): # Specify the loop condition (you can use while or for)nodel = Nonenode2 = Nonemerged = None # Create a new node by merging the two popped nodespass # Remember to specify the left and right children nodes for mergedpass # Insert the new node to the tree### END YOUR CODE ###In [ 1: # Do not change the test code heresample_text = 'No, it is a word. What matters is the connection the word implies.'freq = create_frequency_dict(sample_text)tree = create_tree(freq)print('Before merge, len(tree) = ', len(tree))print()merge_nodes (tree)print('After merge, len(tree) = ', len(tree))Expected outputBefore merge, len(tree) = 20After merge, len(tree) = 1

def merge_nodes (tree): ### START YOUR CODE ### while(len(tree)>1): # Specify the Loop condition…

then merging them to a new node, and lastly inserting the new node back to tree. Note that: The new node does not need to have a self.char attribute, so you can let it be None . Remember to specify the left and right children nodes correctly for the new node. The function changes tree in place. So, vou don't need to return tree

then merging them to a new node, and lastly inserting the new node back to tree. Note that: The new node does not need to have a self.char attribute, so you can let it be None . Remember to specify the left and right children nodes correctly for the new node. The function changes tree in place. So, vou don't need to return tree

Computer Networking: A Top-Down Approach (7th Edition)

7th Edition

ISBN:9780133594140

Author:James Kurose, Keith Ross

Publisher:James Kurose, Keith Ross

Chapter1: Computer Networks And The Internet

Section: Chapter Questions

Problem R1RQ: What is the difference between a host and an end system? List several different types of end...

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Question

Implement the following function, in which a while loop is used to keep taking out two minimum elements from the tree, by calling heapq.heappop (), and
then merging them to a new node, and lastly inserting the new node back to tree.
Note that:
• The new node does not need to have a self.char attribute, so you can let it be None
Remember to specify the left and right children nodes correctly for the new node.
The function changes tree in place. So, you don't need to return tree
In [ ]: def merge_nodes (tree):
### START YOUR CODE ###
while(len(tree)>1): # Specify the loop condition (you can use while or for)
nodel = None
node2 = None
merged = None # Create a new node by merging the two popped nodes
pass # Remember to specify the left and right children nodes for merged
pass # Insert the new node to the tree
### END YOUR CODE ###
In [ 1: # Do not change the test code here
sample_text = 'No, it is a word. What matters is the connection the word implies.'
freq = create_frequency_dict(sample_text)
tree = create_tree(freq)
print('Before merge, len(tree) = ', len(tree))
print()
merge_nodes (tree)
print('After merge, len(tree) = ', len(tree))
Expected output
Before merge, len(tree) = 20
After merge, len(tree) = 1

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