Fear of heights - A psychologist has developed a new treatment for acrophobia (the extreme fear of heights) and wants to compare the results of thisnew treatment to the results of the standard treatment. A study is conducted where a random sample of 16 patients undergo the new treatment andtheir improvement scores on a diagnostic test are compared to a control sample of 13 patients who received the standard treatment. Summary scoresfor both groups are shown in the table below.Treatment Sample Mean Sample Standard DeviationNew50.912Standard47.211.4The degrees of freedom for this problem is d f26.287709.1. Select the hypotheses that should be used to assess if the new treatment results in higher average improvement scores than the standard treatment.А. Но : И1= µ2 vs. Ha : H1 # µ2OB. Ho : µ1 = µ2 vS. Ha : H1 < µ2ос. Но : Иј — И2 vs. Ha : Hi > H22. Calculate the test statistic.?V =3. Calculate the p-value.p-value =

Given Data : For Sample 1 x̄1 = 50.9 s1 = 12.0 n1 = 16 For Sample 2…

Answered: their improvement scores on a…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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In a test of the effectiveness of garlic for lowering cholesterol, 49 subjects were treated with raw garlic. Cholesterol levels were measured before and after the treatment. The changes (before minus after) in their levels of LDL cholesterol (in mg/dL) have a mean of 0.9 and a standard deviation of 2.33 . Use a 0.10 significance level to test the claim that with garlic treatment, the mean change in LDL cholesterol is greater than 0 . What do the results suggest about the effectiveness of the garlic treatment? Assume that a simple random sample has been selected. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim. What are the null and alternative hypotheses? A. Upper H 0 : mu greater than0 mg/dL Upper H 1 : mu less than0 mg/dL B. Upper H 0 : mu equals0 mg/dL Upper H 1 : mu less than0 mg/dL C. Upper H 0 : mu…
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In a test of the effectiveness of garlic for lowering cholesterol, 64 subjects were treated with raw garlic. Cholesterol levels were measured before and after the treatment. The changes (before minus after) in their levels of LDL cholesterol (in mg/dL) have a mean of 0.9 and a standard deviation of 16.9 . Use a 0.01 significance level to test the claim that with garlic treatment, the mean change in LDL cholesterol is greater than 0 . What do the results suggest about the effectiveness of the garlic treatment? Assume that a simple random sample has been selected. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim. What are the null and alternative hypotheses? A. Upper H 0 : mu equals0 mg/dL Upper H 1 : mu greater than0 mg/dL B. Upper H 0 : mu greater than0 mg/dL Upper H 1 : mu less than0 mg/dL C. Upper H 0 : mu…
A researcher wanted to know whether losing one night sleep can affect problem solving. A sample of n = 25 college students was given a problem-solving task at noon on one day and again at noon on the following day. The students were not permitted any sleep between the two tests. For each student, the difference between the first and the second score was recorded: MD = 5 and standard deviation of the difference score was s = 10. Do the data indicate a significant change in problem solving ability? Use a two-tailed test with α = .01. The alternative hypothesis in words is Group of answer choices Problem solving ability improves after losing on night sleep Problem solving ability is reduced after losing one night of sleep There is no significant difference in problem solving ability between the two conditions: before and after losing one night of sleep There is a significant difference in problem solving ability between the two conditions: before and after losing one night of…

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