The y-coordinate of a particle in curvilinear motion is given by y = 13.8t3 - 8.5t, where y is in inches and t is in seconds. Also, the particle has an acceleration in the x-direction given by ax = 10.5t in./sec2. If the velocity of the particle in the x-direction is 13.9 in./sec when t = 0, calculate the magnitudes of the velocity v and acceleration a of the particle when t = 2.6 sec. Construct v and a in your solution. Answers: When t = 2.6 sec, V = a = i i in./sec in./sec²
The y-coordinate of a particle in curvilinear motion is given by y = 13.8t3 - 8.5t, where y is in inches and t is in seconds. Also, the particle has an acceleration in the x-direction given by ax = 10.5t in./sec2. If the velocity of the particle in the x-direction is 13.9 in./sec when t = 0, calculate the magnitudes of the velocity v and acceleration a of the particle when t = 2.6 sec. Construct v and a in your solution. Answers: When t = 2.6 sec, V = a = i i in./sec in./sec²
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![The y-coordinate of a particle in curvilinear motion is given by y = 13.8t³ - 8.5t, where y is in inches and t is in
seconds. Also, the particle has an acceleration in the x-direction given by ax = 10.5t in./sec². If the velocity of the
particle in the x-direction is 13.9 in./sec when t = 0, calculate the magnitudes of the velocity v and acceleration a of
the particle when t = 2.6 sec. Construct v and a in your solution.
Answers: When t = 2.6 sec,
V =
a =
i
i
in./sec
in./sec²](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F46dae25a-c1ef-41c1-a2dd-cf24c64a0bae%2Fc467b236-3ad9-464e-9f83-01fc800102c8%2Fu51n59s_processed.png&w=3840&q=75)
Transcribed Image Text:The y-coordinate of a particle in curvilinear motion is given by y = 13.8t³ - 8.5t, where y is in inches and t is in
seconds. Also, the particle has an acceleration in the x-direction given by ax = 10.5t in./sec². If the velocity of the
particle in the x-direction is 13.9 in./sec when t = 0, calculate the magnitudes of the velocity v and acceleration a of
the particle when t = 2.6 sec. Construct v and a in your solution.
Answers: When t = 2.6 sec,
V =
a =
i
i
in./sec
in./sec²
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