The x-coordinate of a particle in curvilinear motion is given by x = 3.9t3 - 1.6t where x is in feet and tis inseconds. The y-component of acceleration in feet per second squared is given by a, = 5.2t. If the particle has y-components y = 0 and vy = 3.7 ft/sec when t = 0, find the magnitudes of the velocity v and acceleration a when t= 2.8 sec. Sketch the path for the first 2.8 seconds of motion, and show the velocity and acceleration vectors fort = 2.8 sec.%3DAnswers:V =ift/seca =ift/sec?

Given, x=3.9t3-1.6tay=5.2 ty=0, vy=3.7 ft/secwhen t=0when, t=2.8…

Answered: The x-coordinate of a particle in…

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