The x-coordinate of a particle in curvilinear motion is given by x = 4.8t³-2.7t where x is in feet and t is in seconds. The y-component acceleration in feet per second squared is given by ay = 2.9t. If the particle has y-components y = 0 and vy= 3.8 ft/sec when t=0, find the magnitudes of the velocity v and acceleration a when t = 4.8 sec. Sketch the path for the first 4.8 seconds of motion, and show the velocity and acceleration vectors for t = 4.8 sec. Answers: V= a- i ! ft/sec ft/sec²
The x-coordinate of a particle in curvilinear motion is given by x = 4.8t³-2.7t where x is in feet and t is in seconds. The y-component acceleration in feet per second squared is given by ay = 2.9t. If the particle has y-components y = 0 and vy= 3.8 ft/sec when t=0, find the magnitudes of the velocity v and acceleration a when t = 4.8 sec. Sketch the path for the first 4.8 seconds of motion, and show the velocity and acceleration vectors for t = 4.8 sec. Answers: V= a- i ! ft/sec ft/sec²
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![The x-coordinate of a particle in curvilinear motion is given by x - 4.8t3-2.7t where x is in feet and t is in seconds. The y-component of
acceleration in feet per second squared is given by ay = 2.9t. If the particle has y-components y = 0 and vy = 3.8 ft/sec when t = 0, find
the magnitudes of the velocity v and acceleration a when t = 4.8 sec. Sketch the path for the first 4.8 seconds of motion, and show the
velocity and acceleration vectors for t = 4.8 sec.
Answers:
V=
a=
i
i
! ft/sec
ft/sec²](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2106de34-9293-4614-8bd1-07520f8b392f%2F12056e5c-43e5-4036-95da-c6d877a68642%2Fa46c7sw_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The x-coordinate of a particle in curvilinear motion is given by x - 4.8t3-2.7t where x is in feet and t is in seconds. The y-component of
acceleration in feet per second squared is given by ay = 2.9t. If the particle has y-components y = 0 and vy = 3.8 ft/sec when t = 0, find
the magnitudes of the velocity v and acceleration a when t = 4.8 sec. Sketch the path for the first 4.8 seconds of motion, and show the
velocity and acceleration vectors for t = 4.8 sec.
Answers:
V=
a=
i
i
! ft/sec
ft/sec²
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