The world's deepest gold mine, which is located in South Africa, is over 5.3 km deep. Every day, the mine transfers enough energy by heat to the mine's cooling systems to melt 364320 kg of ice at 0.0 degrees Celsius. If the energy output from the mine is increased by 3.3 percent, to what final temperature will the 364320 kg of ice-cold water be heated? Latent Heat of fusion of Ice = 3.33 × 105 J/kg Specific heat capacity of Water = 4186J/(kg. °C)

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**The World's Deepest Gold Mine: An Energy Perspective**

The world’s deepest gold mine, located in South Africa, extends to over 5.3 km in depth. Each day, the mine's cooling systems transfer sufficient energy by heat to melt 364,320 kg of ice at 0.0 degrees Celsius.

**Understanding Energy Transfer in the Mine:**

If the energy output from the mine is increased by 3.3%, we need to determine the final temperature to which the 364,320 kg of ice-cold water will be heated.

**Given Data:**

- **Latent Heat of Fusion of Ice:** \( 3.33 \times 10^5 \) J/kg
- **Specific Heat Capacity of Water:** \( 4186 \) J/(kg·°C)

**Conceptual Explanation:**

1. **Latent Heat of Fusion:** This is the amount of energy required to change a unit mass of a substance from solid to liquid at constant temperature. For ice, this value is \( 3.33 \times 10^5 \) J/kg.

2. **Specific Heat Capacity:** This is the amount of energy required to raise the temperature of a unit mass of a substance by one degree Celsius. For water, this value is \( 4186 \) J/(kg·°C).

**Problem Statement:**
The task is to calculate the final temperature of the 364,320 kg of water after the energy output from the mine increases by 3.3%.

By understanding these principles and values, students can apply their knowledge of thermodynamics to solve practical problems related to the mining industry and its impact on energy transfer and environmental control.
Transcribed Image Text:**The World's Deepest Gold Mine: An Energy Perspective** The world’s deepest gold mine, located in South Africa, extends to over 5.3 km in depth. Each day, the mine's cooling systems transfer sufficient energy by heat to melt 364,320 kg of ice at 0.0 degrees Celsius. **Understanding Energy Transfer in the Mine:** If the energy output from the mine is increased by 3.3%, we need to determine the final temperature to which the 364,320 kg of ice-cold water will be heated. **Given Data:** - **Latent Heat of Fusion of Ice:** \( 3.33 \times 10^5 \) J/kg - **Specific Heat Capacity of Water:** \( 4186 \) J/(kg·°C) **Conceptual Explanation:** 1. **Latent Heat of Fusion:** This is the amount of energy required to change a unit mass of a substance from solid to liquid at constant temperature. For ice, this value is \( 3.33 \times 10^5 \) J/kg. 2. **Specific Heat Capacity:** This is the amount of energy required to raise the temperature of a unit mass of a substance by one degree Celsius. For water, this value is \( 4186 \) J/(kg·°C). **Problem Statement:** The task is to calculate the final temperature of the 364,320 kg of water after the energy output from the mine increases by 3.3%. By understanding these principles and values, students can apply their knowledge of thermodynamics to solve practical problems related to the mining industry and its impact on energy transfer and environmental control.
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