**Title: Understanding the Energy Dynamics of the World’s Deepest Gold Mine**The world's deepest gold mine, located in South Africa, extends over 6.6 km deep into the Earth. Each day, this mine encounters significant thermal energy that must be managed. A fascinating aspect of this is the amount of energy transferred by heat to the mine’s cooling systems, which is enough to melt a substantial mass of ice.To put this into perspective:- **Energy Transfer for Melting Ice:** The mine transfers enough energy by heat to melt 363,147 kg of ice at 0.0 degrees Celsius.**Problem Statement:**If the energy output from the mine increases by 9.3 percent, to what final temperature will the 363,147 kg of ice-cold water be heated?**Given Data:**1. *Latent Heat of Fusion of Ice*: \( 3.33 \times 10^5 \, \text{J/kg} \)2. *Specific Heat Capacity of Water*: \( 4186 \, \text{J/(kg·°C)} \)**Objective:**Calculate the final temperature to which the 363,147 kg of ice-cold water (initially at 0°C) will be heated when the energy output from the mine increases by 9.3 percent.**Possible Answers:**a. 26.11 °Cb. 48.83 °Cc. 14.17 °Cd. 3.78 °Ce. 7.40 °C**Explanation of Calculation Process:**1. **Calculate the energy required to melt the ice:** \[ Q_{\text{melt}} = m \times \text{Latent Heat of Fusion} \] Where, - \( m \) = mass of ice = 363,147 kg - Latent Heat of Fusion = \( 3.33 \times 10^5 \, \text{J/kg} \) Therefore, \[ Q_{\text{melt}} = 363,147 \, \text{kg} \times 3.33 \times 10^5 \, \text{J/kg} = 1.21 \times 10^{11} \, \text{J} \]2. **Account for the 9.3% increase in

Given : Mass of ice (m) = 363147 kg Energy increased by 9.3 % Latent Heat of fusion of Ice (L) =…

the mine transfers enough energy by heat to the mine's cooling systems to melt 363147 kg of ice at 0.0 degrees Celsius. If the energy output from the mine is increased by 9.3 percent, to what final temperature will the 363147 kg of ice-cold water be heated? Latent Heat of fusion of Ice = 3.33 × 105 J/kg Specific heat capacity of Water = 4186J/(kg. °C) a. 26.11 b. 48.83 c. 14.17 d. 3.78 e. 7.40

the mine transfers enough energy by heat to the mine's cooling systems to melt 363147 kg of ice at 0.0 degrees Celsius. If the energy output from the mine is increased by 9.3 percent, to what final temperature will the 363147 kg of ice-cold water be heated? Latent Heat of fusion of Ice = 3.33 × 105 J/kg Specific heat capacity of Water = 4186J/(kg. °C) a. 26.11 b. 48.83 c. 14.17 d. 3.78 e. 7.40

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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