The work done in moving a positive charge against an electric field does not depend on the path chosen in moving the charge in that field. Based on the statement, what kind of force field is the electrostatic field?
Q: An electron has an initial speed of 6.31 106 m/s in a uniform 4.22 105 N/C strength electric field.…
A: Given value--- initial speed = 6.31 × 10⁶ m/s. Electric field = 4.22 × 10⁵ N/C. We have to find---…
Q: Two charges, q1=-0.72mC and q2=-1.89mC are placed 6.33m apart from one another (mC stand for "milli-…
A: Given: The two charges are q1=-0.72 mC and q2=-1.89 mC. The operation between charges is 6.33 m.
Q: Find the ratio of the magnitudes of the electrical and the gravitational forces acting between a…
A: Magnitude of charge of proton = magnitude of charge of electron = 1.6 ×10-19 CMass of electron =…
Q: A droplet of ink in an industrial ink-jet printer carries a charge of 1.9×10^-10C and is deflected…
A:
Q: A droplet of ink in an industrial ink-jet printer carries a charge of 1.7×10−10C1.7×10−10C and is…
A:
Q: An electron is moving along the B field with speed v, to the right. What is the direction of the…
A: The electron is moving along the field B with a speed v, towards right.
Q: Chapter 18 Problem 3: Suppose two equal charges of 0.85 C each are separated by a distance of 2.5…
A: The objective of the question is to calculate the magnitude of the force acting between two charges…
Q: The charge per unit length on a long, straight filament is -92.0 µC/m. (a) Find the electric field…
A:
Q: Suppose a 40 x 10-9 Coulomb charged object is placed into a uniform electric field and it feels a…
A:
Q: An electron with an initial speed of 5.5 x 10 m/s enters a uniform electric field that acts only to…
A: Given Initial velocity = u = 5.5 x 10 m/s Strength of electric field = E = 3.7 x 10 N/C We have to…
Q: Between two plates, the electric field is 5.0 103 N/C directed downward. What is the magnitude and…
A: Electric field is equal to the electric force per unit charge. And the direction of electric field…
Q: There are two charges on the x axis, a 1 C charge at x=-1 meter and a -2 C charge at x=1 meter. At…
A:
Q: A proton (charge +?=1.602 ? 10^−19 ?) moves a distance d = 0.30 m in a straight line between points…
A: The force in a charge particle with charge q in an electric field E, is equal to qE . Work done by a…
Q: Where should a -10-6 C charged object be located on line between the positively charged objects…
A: The objective of the question is to find the position where a negatively charged object should be…
Q: Two charged particles apply an electric force of 5.2 × 10^-3 N on each other. Distance between them…
A: Given: Electric force between the charges F=5.2×10-3N, New distance between the charges dnew=2d.…
Q: If a +25µC charge experiences an electrostatic force with a magnitude of 1.2N pointing to the left,…
A:
Q: A proton accelerates from rest in a uniform electric field of 605 N/C. At some later time, its speed…
A:
Q: s the direction of the electrostatic force exerted on the electron by the proton along a straight…
A: The electrostatic force between electron and proton is attractive in nature.The electron will be…
Q: What is the direction and magnitude of an electric field that supports the weight of a free electron…
A: The weight of the electron is W=mg where m is the mass of the electron and g is the acceleration due…
Q: A particle with a charge of 8.30 nC is in a uniform electric field directed to the left. Another…
A: Work done is given by change in kinetic energy
Q: Consider the +1 nC (nano = 10°) charge with the two others: +1 nC %3D +2 nC +) (a) (10) What is the…
A: a) From Coulomb's law, the magnitude of the electrostatic force between two charges is given as;…
Q: When point charges q₁ = +2.9 µC and q2 = +2.5 µC are brought near each other, each experiences a…
A:
Q: A positively charged rod is brought close to a neutral piece of paper, which it attracts. Draw a…
A: A positively charged rod is brought close to a neutral piece of paper, which it attracts. We have to…
Trending now
This is a popular solution!
Step by step
Solved in 3 steps with 2 images
- A particle with a charge of +4.20 nC is in a uniform elec- tric field É directed to the left. It is released from rest and moves to the left; after it has moved 6.00 cm, its kinetic energy is found to be +1.50 X 10 J. (a) What work was done by the electric force?Please AsapAn electron in a uniform electric field experiences a force due east. If the electron is replaced with a proton, in which direction will it experience a force? Question 3 options: North East South West
- #11) The figure below shows an electron passing between two charged metal plates that create a 100 N/C vertical electric field perpendicular to the electron’s original horizontal velocity. (These can be used to change the electron’s direction, such as in an oscilloscope.) The initial speed of the electron is 3.00 x 106 m/s, and the horizontal distance it travels in the uniform field is 4.00 cm. a) What is its vertical deflection? b) What is the vertical component of its final velocity? c) At what angle does it exit? Neglect any edge effects. (Please answer C)A constant electric field accelerates a proton from rest through a distance of 2.15 m to a speed of 1.65 × 105 m/s. (The mass and charge of a proton are mp 1.67 x 10 HINT (a) Find the change in the proton's kinetic energy (in J). J (b) Find the change in the system's electric potential energy (in J). J (c) Calculate the magnitude of the electric field (in N/C). N/C kg and 9p = e = 1.60 x 10 C.)Calculate the work required to bring a charge of 5.9×10−95.9×10−9 C from infinity to a point 28.7 cm from a charge of 0.0390.039 μμC in vacuum. Use the value of Coulomb's constant ke=14πε0=9×109ke=14πε0=9×109 m/F. Provide your answer in units of 10−610−6 J: for example, if your answer is 3.6×10−63.6×10−6, then enter 3.6 as your answer.
- A small negatively charged particle is placed between two charged plates. The mass of the particle is m = 7.5 µg and its charge is q = -2.5 nC. The left plate is positively charged and the right plate is negatively charged. (a) Draw the direction of the electric field between the plates on the diagram below. (b) In which direction does the particle move? ( (c) The plates produce a uniform electric field with magnitude E 120 N/C. Calculate the force acting on the particle. (d) What is the particle's acceleration? For parts (c) and (d), include both magnitude and direction. + + + + + 111111 1Use the similarity between Coulomb's Law and the Law of Universal Gravitation to calculate the distance of closest approach between a point charge of +8.55 × 10-6 C, which starts at infinity with kinetic energy of 5.45 J, and a fixed point charge of +5.30 × 104 C. Assume that the moving charge is aimed straight at the fixed point charge.A particle with mass m = 4.50 mg and charge Q = 75.0 μC enters a region of space where there exists an electric field between two vertically arranged parallel conducting plates, which carry opposite charges - these charges establish the field between the plates. The particle enters via a hole in the positively charged plate and after a short time leaves the region via a hole in the negatively charged plate as shown in Figure 2. The field between the plates is 3, 150 ÎN C¹. If the plates are 15.0 cm apart, and the particle enters with a speed of 5.70 x 10²m s¹, determine the speed of the particle as it exits the region between the plates. V Figure 2: