A particle with mass m = 4.50 mg and charge Q = 75.0μC enters a region of space where there exists an electric field between two vertically arranged parallel conducting plates, which carry opposite charges - these charges establish the field between the plates. The particle enters via a hole in the positively charged plate and after a short time leaves the region via a hole in the negatively charged plate as shown in Figure 2. The field between the plates is 3, 150 ÎN C1. If the plates are 15.0 cm apart, and the particle enters with a speed of 5.70 x 10²m s¹, determine the speed of the particle as it exits the region between the plates.

A particle with mass m = 4.50 mg and charge Q = 75.0μC enters a region of space where there exists an electric field between two vertically arranged parallel conducting plates, which carry opposite charges - these charges establish the field between the plates. The particle enters via a hole in the positively charged plate and after a short time leaves the region via a hole in the negatively charged plate as shown in Figure 2. The field between the plates is 3, 150 ÎN C1. If the plates are 15.0 cm apart, and the particle enters with a speed of 5.70 x 10²m s¹, determine the speed of the particle as it exits the region between the plates.

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Similar questions

An electron is placed at rest in an electric field of 510 N/C. Which of the followings is the speed of the electron 47.0 ns after being released? ( e = 1,6 × 10-19C,e, = 8,85 × 10-12c²/N.m², mej= 9,11× 10-31kg, m, = 1,67 × 10-27kg) Your answer: O A)1.4 x 105 m/s O B) 0.8 x 106 m/s O ) 0.3 x 104 m/s O D) 2.6 x 106 m/s O E)4.2 x 106 m/s
show your full solution.
A capacitor is composed of two metal plates. The two plates have the dimensions L = 0.11 m and W = 0.56 m. The plates have a distance between them of d = 0.1 m, and are parallel to each other. Part (a) The plates are connected to a battery and charged such that the first plate has a charge of q. Write an expression for the magnitude of the electric field, |E|, halfway between the plates. Part (b) Input an expression for the magnitude of the electric field, |E2|, just in front of plate two. Part (c) If plate two has a total charge of q = -1 mC, what is its charge density, σ, in C/m2?
An electron, initially at rest is placed in an electric field of 5x10 N/C directed west. What is the acceleration of the electron due to the electric field? O 4.79x10^13 ms^2 O 8.78x10^-16 ms^2 8.78x10^16 m's^2 O 4.79x10^-13 m/s^2
In a typical television or in an older computer picture tube (CRT), the electrons that strike the screen to form an image are accelerated between two charged plates that have a potential difference of 2.5×104 V. The plates are separated by a distance of 1.3 cm. Assuming that there is a uniform electric field between the plates, calculate the strength of the field.
Charge q, = 2.50 nC is at x, = 0 and charge q, = 6.00 nC is at x, = 4.00 m. At what point between the two charges is the electric field equal to zero? (Enter the x coordinate in m.) HINT Write an expression for the net electric field as a function of position, x, in the region between the two charges. (Don't forget that the electric field is a vector, so direction is important!) Set this expression equal to zero and solve for the variable x using the quadratic equation. Click the hint button again to remove this hint. m
The figure shows an electric dipole. What is the magnitude of the dipole's electric field at point P? Assume that q = 9.85 x 106 C,d= 6.97 x 10-6 m, and r = 0.403 cm. +q+ Number i 9440530.064 N/C or V/m d/2 d/2 -9 Units
A small negatively charged particle is placed between two charged plates. The mass of the particle is m = 7.5 µg and its charge is q = -2.5 nC. The left plate is positively charged and the right plate is negatively charged. (a) Draw the direction of the electric field between the plates on the diagram below. (b) In which direction does the particle move? ( (c) The plates produce a uniform electric field with magnitude E 120 N/C. Calculate the force acting on the particle. (d) What is the particle's acceleration? For parts (c) and (d), include both magnitude and direction. + + + + + 111111 1
An electric dipole composed of two charges of magnitude 7.01 μC separated by 99.1 cm is in a uniform 5.03 x 106 N/C electric field. How much energy (in J) is required to change the dipole's orientation from parallel to antiparallel to the field?
A pair of charged conducting plates produces a uniform field of 20,000 N/C, directed to the right, between the plates. The separation of the plates is 50 mm. A proton is projected from plate A, directly toward plate B, with an initial speed of vo = 1.0 × 105 m/s. What is the speed of the proton as it strikes plate B? Vo Provide the solution:___ x105 m/s + +
A 6 g ball with a charge of 4 μC hangs by a thread between two oppositely charged parallel plates as shown below. The distance between the ball & the edges of the plates is much greater than the distance between the plates. Each plate has the same constant uniform charge density. A + 30° Determine the voltage between the plates. -61.9806 V X 67.8963916567 V Determine the polarity of each plate. You will not receive credit until you have correctly selected the polarities of both plates. left plate neutral right plate impossible to determine 8 mm ×
A proton accelerates from rest in a uniform electric field of 480 N/C and expires for a while. its speed is 1.8x 10^6 m/s. How far did the proton travel in 5.2x10^-5 s? A) 62.2 m B) 28.6 m C) 54.8 m D) 36.2 m E) 24.7 m