An electron beam in an oscilloscope is deflected by the electric field produced by oppositely charged metal plates. If the electric field between the plates is 1.70 x 105 N/C directed downward, what is the force on each electron when it passes between the plates?
An electron beam in an oscilloscope is deflected by the electric field produced by oppositely charged metal plates. If the electric field between the plates is 1.70 x 105 N/C directed downward, what is the force on each electron when it passes between the plates?
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![### Question:
An electron beam in an oscilloscope is deflected by the electric field produced by oppositely charged metal plates. If the electric field between the plates is \(1.70 \times 10^5 \, \text{N/C}\) directed downward, what is the force on each electron when it passes between the plates?
### Answer:
\[2.72 \times 10^{-14} \, \text{N upward} \]
### Explanation:
This problem involves understanding how an electric field interacts with charged particles, such as electrons, in an oscilloscope. The electric field is given as \(1.70 \times 10^5 \, \text{N/C}\) and is directed downward. The force on each electron, given its charge, acts in the opposite direction of the electric field (upward), as indicated by the calculated force \(2.72 \times 10^{-14} \, \text{N}\) upward.
No graphs or diagrams are provided in this problem.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F528734fa-2f56-42f1-ac26-0d1ff4e0efca%2F893f997b-b047-4175-9fb9-0d61b07e196c%2Feupwdhy_processed.png&w=3840&q=75)
Transcribed Image Text:### Question:
An electron beam in an oscilloscope is deflected by the electric field produced by oppositely charged metal plates. If the electric field between the plates is \(1.70 \times 10^5 \, \text{N/C}\) directed downward, what is the force on each electron when it passes between the plates?
### Answer:
\[2.72 \times 10^{-14} \, \text{N upward} \]
### Explanation:
This problem involves understanding how an electric field interacts with charged particles, such as electrons, in an oscilloscope. The electric field is given as \(1.70 \times 10^5 \, \text{N/C}\) and is directed downward. The force on each electron, given its charge, acts in the opposite direction of the electric field (upward), as indicated by the calculated force \(2.72 \times 10^{-14} \, \text{N}\) upward.
No graphs or diagrams are provided in this problem.
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