A particle with a charge of 8.30 nC is in a uniform electric field directed to the left. Another force,in addition to the electric force, acts on the particle so that when it is released from rest, it movesto the right. After it has moved a distance of 5.00 cm, the additional force has done an amount ofwork equal to 7.90×10-5 J and the particle has kinetic energy equal to 3.90x10-5 J.What work was done by the electric force?Express your answer in joules.HV ΑΣφ?WE =JSubmitRequest AnswerPart BWhat is the potential of the starting point with respect to the endpoint?Express your answer in volts.?VSubmitRequest AnswerPart CWhat is the magnitude of the electric field?Express your answer in volts per meter.?E =V/mSubmitRequest Answer

Work done is given by change in kinetic energy

A particle with a charge of 8.30 nC is in a uniform electric field directed to the left. Another force, in addition to the electric force, acts on the particle so that when it is released from rest, it moves to the right. After it has moved a distance of 5.00 cm, the additional force has done an amount of work equal to 7.90x10-5 J and the particle has kinetic energy equal to 3.90×10-5 J What work was done by the electric force? Express your answer in joules. WE = J Submit Request Answer • Part B What is the potential of the starting point with respect to the endpoint? Express your answer in volts. Πν ΑΣφ V Submit Request Answer Part C What is the magnitude of the electric field? Express your answer in volts per meter. Πνα ΑΣφ E = V/m Submit Request Answer

A particle with a charge of 8.30 nC is in a uniform electric field directed to the left. Another force, in addition to the electric force, acts on the particle so that when it is released from rest, it moves to the right. After it has moved a distance of 5.00 cm, the additional force has done an amount of work equal to 7.90x10-5 J and the particle has kinetic energy equal to 3.90×10-5 J What work was done by the electric force? Express your answer in joules. WE = J Submit Request Answer • Part B What is the potential of the starting point with respect to the endpoint? Express your answer in volts. Πν ΑΣφ V Submit Request Answer Part C What is the magnitude of the electric field? Express your answer in volts per meter. Πνα ΑΣφ E = V/m Submit Request Answer

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter20: Electric Potential And Capacitance

Section: Chapter Questions

Problem 3OQ: A proton is released from rest at the origin in a uniform electric field in the positive x direction...

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Electric Charges and Fields

One of the fundamental properties is the electromagnetic property. Charge cannot be destroyed by any process and this contributes formally to the law of charge conservation.

Question

A particle with a charge of 8.30 nC is in a uniform electric field directed to the left. Another force,
in addition to the electric force, acts on the particle so that when it is released from rest, it moves
to the right. After it has moved a distance of 5.00 cm, the additional force has done an amount of
work equal to 7.90×10-5 J and the particle has kinetic energy equal to 3.90x10-5 J.
What work was done by the electric force?
Express your answer in joules.
HV ΑΣφ
?
WE =
J
Submit
Request Answer
Part B
What is the potential of the starting point with respect to the endpoint?
Express your answer in volts.
?
V
Submit
Request Answer
Part C
What is the magnitude of the electric field?
Express your answer in volts per meter.
?
E =
V/m
Submit
Request Answer

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