A particle with a charge of 8.30 nC is in a uniform electric field directed to the left. Another force,in addition to the electric force, acts on the particle so that when it is released from rest, it movesto the right. After it has moved a distance of 5.00 cm, the additional force has done an amount ofwork equal to 7.90×10-5 J and the particle has kinetic energy equal to 3.90x10-5 J.What work was done by the electric force?Express your answer in joules.HV ΑΣφ?WE =JSubmitRequest AnswerPart BWhat is the potential of the starting point with respect to the endpoint?Express your answer in volts.?VSubmitRequest AnswerPart CWhat is the magnitude of the electric field?Express your answer in volts per meter.?E =V/mSubmitRequest Answer

Work done is given by change in kinetic energy

A particle with a charge of 8.30 nC is in a uniform electric field directed to the left. Another force, in addition to the electric force, acts on the particle so that when it is released from rest, it moves to the right. After it has moved a distance of 5.00 cm, the additional force has done an amount of work equal to 7.90x10-5 J and the particle has kinetic energy equal to 3.90×10-5 J What work was done by the electric force? Express your answer in joules. WE = J Submit Request Answer • Part B What is the potential of the starting point with respect to the endpoint? Express your answer in volts. Πν ΑΣφ V Submit Request Answer Part C What is the magnitude of the electric field? Express your answer in volts per meter. Πνα ΑΣφ E = V/m Submit Request Answer

A particle with a charge of 8.30 nC is in a uniform electric field directed to the left. Another force, in addition to the electric force, acts on the particle so that when it is released from rest, it moves to the right. After it has moved a distance of 5.00 cm, the additional force has done an amount of work equal to 7.90x10-5 J and the particle has kinetic energy equal to 3.90×10-5 J What work was done by the electric force? Express your answer in joules. WE = J Submit Request Answer • Part B What is the potential of the starting point with respect to the endpoint? Express your answer in volts. Πν ΑΣφ V Submit Request Answer Part C What is the magnitude of the electric field? Express your answer in volts per meter. Πνα ΑΣφ E = V/m Submit Request Answer

Physics for Scientists and Engineers: Foundations and Connections

1st Edition

ISBN:9781133939146

Author:Katz, Debora M.

Publisher:Katz, Debora M.

Chapter26: Electric Potential

Section: Chapter Questions

Problem 65PQ: Two 5.00-nC charged particles are in a uniform electric field with a magnitude of 625 N/C. Each of...

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