The window of a room is made of 5 mm thick glass which has a thermal conductivity of 1.4 W/m-K. A heater is used to maintain the room temperature at 22 °C. Take the convection heat transfer coefficients on the outer surface of the window to be 12 W/m²-K. Take appropriate assumptions while solving this problem. (a) T₁-15 °C T↑ Find the outside temperature? -A=1m x 3m 3m², k=1.4 W/m-K Figure Q2 -T₂=5°C L=0.005m
The window of a room is made of 5 mm thick glass which has a thermal conductivity of 1.4 W/m-K. A heater is used to maintain the room temperature at 22 °C. Take the convection heat transfer coefficients on the outer surface of the window to be 12 W/m²-K. Take appropriate assumptions while solving this problem. (a) T₁-15 °C T↑ Find the outside temperature? -A=1m x 3m 3m², k=1.4 W/m-K Figure Q2 -T₂=5°C L=0.005m
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
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![Question 4
The window of a room is made of 5 mm thick glass which has a thermal conductivity of 1.4 W/m-K.
A heater is used to maintain the room temperature at 22 °C. Take the convection heat transfer
coefficients on the outer surface of the window to be 12 W/m²-K.
Take appropriate assumptions while solving this problem.
(a)
T₁-15°C
T↑
-A= 1m x 3m 3m²,
k=1.4W/m-K
Find the outside temperature?
-T₂=5°C
* L=0.005m
Figure Q2](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fdb931eb9-893c-4bd4-b70a-7a8d804a34c6%2F0bd3b1ab-f8f8-4545-b497-e863185fef3f%2F0lo32pa_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Question 4
The window of a room is made of 5 mm thick glass which has a thermal conductivity of 1.4 W/m-K.
A heater is used to maintain the room temperature at 22 °C. Take the convection heat transfer
coefficients on the outer surface of the window to be 12 W/m²-K.
Take appropriate assumptions while solving this problem.
(a)
T₁-15°C
T↑
-A= 1m x 3m 3m²,
k=1.4W/m-K
Find the outside temperature?
-T₂=5°C
* L=0.005m
Figure Q2
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