To confirm that a double-pane window is indeed better than a single-pane window, you ran some tests. A 1.5 mx3 m double-pane window as shown in the figure is used for a comparison of heat loss with an equivalent single-pane window. The window is placed in a test environment where the inside air temperature is 300 K and the outside air temperature is 270 K, as shown in the figure. The thermal conductivity of glass is approximated as 0.93 W/m-K and that of air is approximated as 0.029 W/m-K. Consider the air between the two panes of the double-pane window to be stagnant (not even natural convection is taking place). The convection coefficient on both sides (i.e., inside and outside) of the window is 15 W/m².K. What is the rate of heat transfer through the window? Neglect radiation. 339.8W 2.5 mm Inside 300 K glass 7.5 mm stagnant air glass .5 mm Double-pane Outside 270 K

To confirm that a double-pane window is indeed better than a single-pane window, you ran some tests. A 1.5 mx3 m double-pane window as shown in the figure is used for a comparison of heat loss with an equivalent single-pane window. The window is placed in a test environment where the inside air temperature is 300 K and the outside air temperature is 270 K, as shown in the figure. The thermal conductivity of glass is approximated as 0.93 W/m-K and that of air is approximated as 0.029 W/m-K. Consider the air between the two panes of the double-pane window to be stagnant (not even natural convection is taking place). The convection coefficient on both sides (i.e., inside and outside) of the window is 15 W/m².K. What is the rate of heat transfer through the window? Neglect radiation. 339.8W 2.5 mm Inside 300 K glass 7.5 mm stagnant air glass .5 mm Double-pane Outside 270 K

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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To avoid overheating, natural convection analysis is to be considered. If the minimum allowable heat transfer due to natural convection is 30 W, find the maximum angle at which the TV can hang off the wall (0 < θ < 60). Some temperatures were collected; Back panel surface: 45 °C, ambient: 32 °C. A typical 55-inch TV screen measures (122 cm x 69 cm).
You can neglect radiation at the bottom of the plate; the bottom side of the plate has water flowing underneath it. Often, when dealing with liquids (rather than gases), one can neglect radiation because heat transfer due to convection is so much larger (liquids tend to have higher convection coefficient values than gases).
Find the amount of heat transfer transmitted through a west window (5 m2) 6 mm clear single glass window without interior shading in Amman in July at 15 pm. Assume ho=22.7 W/m2.K and the construction is heavy.
Please include a free body diagram and assumptions
An insulated steam pipe is routed horizontally through an unheated room, then vertically to the ceiling. The pipe is insulated, and the outside diameter of the insulation is 15 cm. The horizontal and vertical lengths of pipe are both 4 m long. The outside-surface temperature of the insulation is 50°C, and the room temperature is 5°C. How much heat is lost from the insulation by convection?
An uninsulated steam pipe passes through a room in which the air and walls are at 25°C. The outside diameter of the pipe is 88 mm, and its surface temperature and emissivity are 200°C and 0.80 respectively. If the coefficient associated with free convection heat transfer from the surface to the air is 15W/m2-k, what is the rate of heat loss for a 5 meter pipe? Round your answer to 2 decimal places.
Example 2: Double-pane window, each window have: Height = 0.8 m Width 1.5 m Thickness = 4 mm k (glass) = 0.78 W/m.K separation between two glasses (air) = 10 mm k (air) = 0.026 W/m.K Temperature of inner surface = 20°C Temperature of outer surface = -10°C Convection heat transfer coefficient on the inner surface h1= 10 W/m2·°C Convection heat transfer coefficient on the outer surface h2= 40 W/m2·°C Determine the heat transfer through the window?
(a) What is the rate of energy loss in watts per square meter through a glass window 2.9 mm thick if the outside temperature is -15°F and the inside temperature is +78°F? (b) A storm window having the same thickness of glass is installed parallel to the first window, with an air gap of 6.8 cm between the two windows. What now is the rate of energy loss if conduction is the only important energy- loss mechanism? (The thermal conductivity of window glass is 1.0 W/m-K, and of air is 0.026 W/m.K.) Jak w (a) Number i (b) Number i Units Units ✪ ✪
If a heat transfer coefficient of 2.84 W l(m2 • K) exists on each of the two inside faces of two sheets of 6.35-mm-thick glass separated by an air gap, calculate the gap that can be used such that the rate of heat transfer by conduction through the air gap equals the rate of heat transfer by convection. What is the rate of heat transfer if this gap is exceeded. The thermal conductivity of air of 0.0242 WI (m . K). Solve for temperature of 20°C and 12°C on the outside surfaces of the glass. Would the calculated gap change in value for different values of the surface temperatures? Would there be any advantage to increasing the gap beyond this calculated value?
i need clear ans by hand and solve very very fast in 20 min and thank you | ᴅʏʙᴀʟᴀ ?✨؛
A distance was measured with an electronic infrared device, during which the influential weather elements prevailing at the time of measurement were measured at The ends of the measurement line were as follows: temperature at the beginning of the line = 26°C; atmospheric pressure at the beginning of the line 680mb; end of line temperature = 32°C; Atmospheric pressure at the end of the line is 670mb. Calculate the amount of correction to be added to the measured distance, given that the length of the carrier wave is The measurement used is 915nm = m Note: - The correction is calculated from the following relationship: 273 N,(ppnm) = (n, - 1)x10* = (n, - 1X X)x10; (n,-1)x10 = 287.604 +- 273+t760 1.6288 0.0136 +-