: The width of a horizontal, rectangular channel is reduced from 3.5 to 2.5 m and the floor is raised by 0.25m in elevation at a given section. At the upper stream section the depth of flow is Im and the KE correction factor is 1.15. If the drop in water level at the contraction is 0.20m. Calculate loss is i) Discharge if energy • zero. ") Discharge if energy loss is 10th of the upper stream velocity head. KE correction factor for contracted section is unity. 2m y₁ 0.2m y: 2 0.25 m. 3.5 2.5m

: The width of a horizontal, rectangular channel is reduced from 3.5 to 2.5 m and the floor is raised by 0.25m in elevation at a given section. At the upper stream section the depth of flow is Im and the KE correction factor is 1.15. If the drop in water level at the contraction is 0.20m. Calculate loss is i) Discharge if energy • zero. ") Discharge if energy loss is 10th of the upper stream velocity head. KE correction factor for contracted section is unity. 2m y₁ 0.2m y: 2 0.25 m. 3.5 2.5m

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Q: Water is flowing in trapezoidal channel with 2V:3H at a discharge of Q=3.5m^3/s. If the channel top…

A: Solution:

Q: 1. Consider a rectangular channel section having a length of 500 feet. The width of the channel is…

Q: In rectangular channel at a section P, it is required that the depth of flow is to be 1.4 m and the…

A: Depth of flow (y)=1.4m Specific energy (E)=2.8m To find Flow condition subcritical, critical, or…

Q: A trapezoidal channel with bottom width of 3 m and side slope of IV: 1.5H carries a discharge of…

A: Bottom Width = 3 m\Side slope = 1V:1.5HDischarge = 8.0 m3/secFlow depth = 1.5 mTo Find :Froude…

Q: A right-angled triangular channel carries a flow of 16,000 l/s. The Manning's n = 0.020 and the…

Q: A rectangular channel discharges 0.5m/s per metre width. Determine the critical depth and the step…

A: Given data: q=0.5 m3/s/m E1=1 m

Q: 1. Water flows in symmetrical trapezoidal channel lined with asphalt has a base width of 4.8 m and…

A: Data givenBase width, B = 4.8 mSide slope = 3 H : 1 Vn = 0.015Channel drop= 0.1 m to every 100 mFind…

Q: Uniform flow (15.0 m³/s) occurs in a rectangular channel of width 3.50m at a normal depth of 3.80m.…

A: Given Width 3.5 mNormal depth before gate 3.8 mDepth at gate 0.5 mDischarge 15 m3/sTo find out Depth…

Q: When the channel of triangular cross section shown in the figure below was new, a flowrate of Q…

A: Given data:- The value of flowrate of Q caused the water to reach, L1=1.9 m Use formula:- Q=AV…

Q: Example. The discharge in a channel with bottom width 3 m is 12 m s. If Manning's n is 0.013 and the…

A: Given that: Bottom width, B=3m Discharge in the channel, Q=12 m3/s…

Q: Water flows within the rectangular channel shown with a flow of 8 m3/s. Given that the specific…

A: Thank you for the question .As per honour code we are allowed answer three subparts at a time so we…

Q: Consider a concrete (n = 0.014) wide rectangular channel that discharges 2.7 m^3/s per unit width of…

A: Data given n = 0.014 Q = 2.7 m3/s / unit width S = 0.0002 Step rise, △z = 0.15 m Find: Flow depth…

Q: For the irregular channel shown, determine: (a) the area of flow, A [m], (b) the wetted perimeter, P…

Q: Part 1: Determine the Froude number and the type of flow. Water flows at a rate of 8.5 m3/s in a…

A: Water flow rate = 8.5m3/sec Width of channel = 2.25m Depth of channel = 0..32m It has been asked in…

Q: A 3 m wide rectangular channel, as shown, carries a flow of 11.7m³/s. hydraulic jump Ус y2 2 Az =…

A: Given data: rectangular channel width = 3 m Discharge = 11.7 m3/s At section 3 hump = 0.4 m

Q: A grass-lined trapezoidal channel is to be designed to carry a flow of 260 cfs. Determine a suitable…

Q: The bottom width and bed slope of a long rectangular channel are 4.0 m and 0.0008, respectively. The…

A: Bottom width of rectangular channel, B=4 m Bed slope of channel, So=0.0008 Steady state discharge,…

Q: Find the maximum step height for a flow with a constant discharge, q = 12 m2 /s, and at 1 a water…

Concept explainers

Time and time related variables in engineering

Time is the event progression starting from past to present and then, future statistically. The time-related variable is any particular value in relation to time to assess its changes on a specified (XY) plane.

Question

: The width of a horizontal, rectangular channel is reduced from
3.5 to 2.5 m and the floor is raised by 0.25m in elevation at a
given section. At the upper stream section the depth of flow is Im
and the KE correction factor is 1.15. If the drop in water level at
the contraction is 0.20m. Calculate
loss is
i) Discharge if
energy
• zero.
") Discharge if energy loss is
10th of the upper stream velocity head.
KE correction factor for contracted section is unity.
2m
y₁
0.2m
y:
2
0.25 m.
3.5
2.5m

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1: Given data.

VIEW

Step 2: Calculation of velocity

VIEW

Step 3: Calculation of discharge when energy loss is zero.

VIEW

Step 4: Calculation of discharge when energy loss is 1/10th of the upper stream velocity head.

VIEW

Solution

VIEW

Step by step

Solved in 5 steps with 6 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Time and time related variables in engineering

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.

Similar questions

Specific energyA horizontal rectangular channel is 12 feet wide and carries a flow rate of 60 cfs. A hump that is 0.5 feet high is placed in the flow path. a. If the normal depth of flow is 1.5 feet, what is the depth of flow over the hump? b. If the normal depth of flow is 0.5 feet, what is the depth of flow over the hump?
2- A rectangular channel has a width of 6 m, carriers a discharge of 24 m³/s with a depth of 3.2 m at Section 1. At Section 2, the flow experiences a smooth and gradual contraction with a minimum width of Bmin to form a critical condition. Assuming energy loss equal to 20% of velocity head at Section 1: a) Calculate the minimum channel width (Bmin) at Section 21 b) Calculate the force (F) exerted from water on the wall by employing the momentum equation 1 B₁ F= F Top veiw 2 Bmin Y1 Side veiw
Calculate the discharge through the channel and the floodway (shown in the Figure below) for steady uniform flow, with S = 0.0009 and y = 8 ft. n = 0.025 ne = 12 m 5 m n=0.040 √ [EXP²] + Р Paper 120 m ZAZ Use the following equivalent channel roughness formula due to Pavlovskii (1931)* Side slopes 1:1 For 25,000 cfs flow through the channel above, find the depth of flow in the floodway when the slope of the energy grade line is 0.0004.
the flow rate is 1.2 m3/s per meter of channel width. (a) Compute the velocity and water depth at the top of the budge (hmax= 0.1 m). Characterize the flow there. (b) Rework the problem for a flow rate three times as large.
The base of the artificial channel has a bottom width of 3m and sides with a slope of 1 vertical to 2 horizontal. The depth of water being predicted/estimated is 1.2m when the discharge is 3.51m3/s. Using Manning's equation with n = 0.022 a. Calculate the slope of the channel bed.b. Calculate the discharge in m3/s when the depth of flow is 1.3m.
Solve 6.3 only
2- A 6-m wide concrete-lined trapezoidal channel (n = 0.013) has a sidewall slope of 1V:1.5H, a longitudinal slope of 0.0005, and carries a discharge of 20 m³/s. Calculate: a) normal depth, Yni b) critical depth, yo c) determine the flow regime based on comparison of yn and yc
Water discharges in too wide rectangular channel slope =0.01 Just apstream the weir where the water depth is 2.5m the flow rate is 5m ^ 3/s As per meter width as shown below Assume n = 0.015 and neglected losses. 1. Find the normal depth, the critical depth and the critical slope? 2. Use the specific energy equation to find the weir height such that the flow over the wer is critical? 3. What water surface profile exists upstream the weir and locate the distance upstream the weit where the water depth equals the normal depth ?
A rectangular concrete channel (n = 0.014) has a bottom width of 5.05 m and a longitudinal slope of 0.002. Compute the discharge rate and velocity for a water depth of 2.34 m. Compute normal depth, critical depth, and critical slope for a discharge of 6.67 m³/s.
Q7: The channel shown in the figure and has a surface of flout finalized concrete 0.1m per 100m of length calculate the discharge (Q) and Froude number (Fr) for a depth of 1.5m, assume n-0.0015 determine Fr is critical, subcritical or supercritical? y=D=1.5m h -3.0m 3 2
Ans. 1.941m/s I need solution #hydraulics
Water is discharged under a sluice gate at a rate of 75 m3 /s into a frictionless, horizontal, rectangular channel, 6 m wide. The depth just downstream of the gate is 1.25 m. Determine the depth just upstream of the gate opening The Froude number upstream and downstream of the sluice gate