The weights of 2-in-1 thirteen inch laptops are normally distributed with an average of 3.19 Ibs (pounds) and a standard deviation of 0.55 Ibs. Sixty (60) percent of this type of laptop weigh more than x Ibs. Which of the following Excel commands can be used to calculate the value of x? O = NORM.INV ( 0,4 ; 3,19; 0,55; TRUE) O = NORM.DIST (0,6 ; 0,4; 3,19 ; 0,55; FALSE) O= NORM.INW (0,6 ; 3,19; 0,55 ) O= NORM.INV ( 0,4 ; 3,19 ; 0,55 ) O = NORM.INV ( 0,4 ; 3,19 ; SQRT(0,55) ) If a random sample of 15 of these laptops is selected, what is the probability that their average weight is less than 3.45 Ibs?

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on 7
The weights of 2-in-1 thirteen inch laptops are normally distributed with an average of 3.19 Ibs (pounds) and a
Finis
standard deviation of 0.55 Ibs.
red
Time
d put of
Sixty (60) percent of this type of laptop weigh more than x Ibs. Which of the following Excel commands can be
used to calculate the value of x?
ag question
O = NORM.INV (0,4 ; 3,199; 0,55 ; TRUE )
O = NORM.DIST (0,6; 0,4 ; 3,19 ; 0,55 ; FALSE )
O = NORM.INV (0,6; 3,19; 0,55 )
O = NORM.IN (0,4; 3,19 ; 0,55 )
O = NORM.INV (0,4 ; 3,19 ; SQRT(0,55) )
If a random sample of 15 of these laptops is selected, what is the probability that their average weight is less than
3.45 lbs?
0.0336
00.4700
0.9131
0.6808
0.9664
Transcribed Image Text:on 7 The weights of 2-in-1 thirteen inch laptops are normally distributed with an average of 3.19 Ibs (pounds) and a Finis standard deviation of 0.55 Ibs. red Time d put of Sixty (60) percent of this type of laptop weigh more than x Ibs. Which of the following Excel commands can be used to calculate the value of x? ag question O = NORM.INV (0,4 ; 3,199; 0,55 ; TRUE ) O = NORM.DIST (0,6; 0,4 ; 3,19 ; 0,55 ; FALSE ) O = NORM.INV (0,6; 3,19; 0,55 ) O = NORM.IN (0,4; 3,19 ; 0,55 ) O = NORM.INV (0,4 ; 3,19 ; SQRT(0,55) ) If a random sample of 15 of these laptops is selected, what is the probability that their average weight is less than 3.45 lbs? 0.0336 00.4700 0.9131 0.6808 0.9664
Expert Solution
Step 1

Given that the mean is 3.19 and the standard deviation is 0.55

Given that

      P(X>x)=60%1-P(Xx)=0.60     P(Xx)=0.40                 x=3.05, from the excel function, =NORM.INV(0.4,3.19,0.55)

Correct option:

=NORM.INV0.40, 3.19, 0.55)

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