Homework Help is Here – Start Your Trial Now!
Math
Probability
(b) According to a certain survey, adults spend 2.45 hours per day watching television on a weekday. Assume that the standard deviation for "time spent watching television on a weekday" is 1.93- hours. If a random sample of 60 adults is obtained, describe the sampling distribution of x, the mean amount of time spent watching television on a weekday. x is approximately normal with ; 2.45 and e;- 249162 (Round to six decimal places as needed.) (c) Determine the probability that a random sample of 60 adults results in a mean time watching television on a weekday of between 2 and 3 hours. The probability is (Round to four decimal places as needed)

(b) According to a certain survey, adults spend 2.45 hours per day watching television on a weekday. Assume that the standard deviation for "time spent watching television on a weekday" is 1.93- hours. If a random sample of 60 adults is obtained, describe the sampling distribution of x, the mean amount of time spent watching television on a weekday. x is approximately normal with ; 2.45 and e;- 249162 (Round to six decimal places as needed.) (c) Determine the probability that a random sample of 60 adults results in a mean time watching television on a weekday of between 2 and 3 hours. The probability is (Round to four decimal places as needed)

A First Course in Probability (10th Edition)
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
See similar textbooks
icon
Related questions
Question

Please help me stepwise and correct pls and show excel output also pls..

The variable "weekly time spent watching television" is likely skewed right, not normally distributed. OB. The variable "weekly time spent watching television" is likely skewed left, not normally distributed. OC. The variable "weekly time spent watching television" is likely symmetric, but not normally distributed. OD. The variable "weekly time spent watching television" is likely normally distributed. OE The variable weekly time spent watching television is likely uniform, not normally distributed. (b) According to a certain survey, adults spend 2.45 hours per day watching television on a weekday. Assume that the standard deviation for "time spent watching television on a weekday" is 1.93) hours. If a random sample of 60 adults is obtained, describe the sampling distribution of x, the mean amount of time spent watching television on a weekday x is approximately normal with u; 2.45 and e;- 249162 (Round to six decimal places as needed.) (e) Determine the probability that a random sample of 60 adults results in a mean time watching television on a weekday of between 2 and 3 hours. The probability is (Round to four decimal places as needed.)
Transcribed Image Text:The variable "weekly time spent watching television" is likely skewed right, not normally distributed. OB. The variable "weekly time spent watching television" is likely skewed left, not normally distributed. OC. The variable "weekly time spent watching television" is likely symmetric, but not normally distributed. OD. The variable "weekly time spent watching television" is likely normally distributed. OE The variable weekly time spent watching television is likely uniform, not normally distributed. (b) According to a certain survey, adults spend 2.45 hours per day watching television on a weekday. Assume that the standard deviation for "time spent watching television on a weekday" is 1.93) hours. If a random sample of 60 adults is obtained, describe the sampling distribution of x, the mean amount of time spent watching television on a weekday x is approximately normal with u; 2.45 and e;- 249162 (Round to six decimal places as needed.) (e) Determine the probability that a random sample of 60 adults results in a mean time watching television on a weekday of between 2 and 3 hours. The probability is (Round to four decimal places as needed.)
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 4 steps with 19 images

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer