The weight of the average 6th grade student's backpack (with books in it) is 18.4 lbs. The principal of the school thinks that the backpack does not weigh 18.4 lbs. What is the null and alternative hypothesis? Ho: μ =18.4 and H1: μ≤18.4 Ho: μ =18.4 and H1: p < 18.4 O Ho: μ = 18.4 and H1: μ > 18.4 Ho: u 18.4 and H1: u 18.4 =
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- Identify the type I error and the type II error that corresponds to the given hypothesis. The proportion of people who write with their left hand is equal to 0.31. Which of the following is a type I error? O A. Fail to reject the claim that the proportion of people who write with their left hand is 0.31 when the proportion is actually 0.31. B. Reject the claim that the proportion of people who write with their left hand is 0.31 when the proportion is actually 0.31. O C. Reject the claim that the proportion of people who write with their left hand is 0.31 when the proportion is actually different from 0.31. D. Fail to reject the claim that the proportion of people who write with their left hand is 0.31 when the proportion is actually different from 0.31.3) see pictures to solveMolly works for a meat producer, and she needs to determine whether containers of ground beef have the correct fat content. She obtains a random sample of 120 containers of ground beef and finds that 84 percent have the correct fat content. Molly then conducts a hypothesis test of H0:p=0.80H0:p=0.80 versus Ha:p≠0.80Ha:p≠0.80 and calculates a test statistic of 1.10 with a pp-value of 0.273. Which of the following best represents the meaning of the pp-value? If the population proportion is 0.84, the probability of observing a sample proportion of 0.80 is 0.273. A If the population proportion is 0.84, the probability of observing a sample proportion of at least 0.04 less than 0.84 is 0.273. B If the population proportion is 0.80, the probability of observing a sample proportion within 0.04 of 0.80 is 0.273. C If the population proportion is 0.80, the probability of observing a sample proportion at least 0.04 greater than 0.80 is 0.273. D If the…
- You hear on the local news that for the city of Kalamazoo, the proportion of people who support President Trump is 0.42. However, you think it is less than 0.42. The hypotheses you want to test are Null Hypothesis: p ≥ 0.42, Alternative Hypothesis: p < 0.42. You take a random sample around town and calculate a p-value for your hypothesis test of 0.7963. What is the appropriate conclusion? Conclude at the 5% level of significance. Question 4 options: 1) We did not find enough evidence to say the proportion of people who support President Trump is larger than 0.42. 2) We did not find enough evidence to say a significant difference exists between the proportion of people who support President Trump and 0.42 3) The proportion of people who support President Trump is significantly less than 0.42. 4) We did not find enough evidence to say the proportion of people who support…Identify the type I error and the type II error that corresponds to the given hypothesis. The proportion of adults who use the internet is greater than 0.27. Which of the following is a type I error? O A. Reject the claim that the proportion of adults who use the internet is 0.27 when the proportion is actually 0.27. O B. Fail to reject the claim that the proportion of adults who use the internet is 0.27 when the proportion is actually different from 0.27. O C. Reject the claim that the proportion of adults who use the internet is 0.27 when the proportion is actually different from 0.27. O D. Fail to reject the claim that the proportion of adults who use the internet is 0.27 when the proportion is actually 0.27. Which of the following is a type II error? O A. Fail to reject the claim that the proportion of adults who use the internet is 0.27 when the proportion is actually 0.27. O B. Reject the claim that the proportion of adults who use the internet is 0.27 when the proportion is…Suppose researchers conducted a study to see if the mean body temperature for adultswas different from 98.6 degrees Fahrenheit. For this study, they took a random sampleof 25 healthy adults and found a mean body temperature of 98.2 degrees Fahrenheit forthe sample with a standard deviation of 0.6 degrees. The temperatures of the sampleparticipants were unimodal and symmetric.a. Write the null hypothesis and alternative hypothesis and define your parameter.b. Show that the necessary conditions (Randomization Condition, 10% Condition,Nearly Normal Condition) are satisfied to perform a hypothesis test. Brieflyexplain how each condition is satisfied.c. Perform the hypothesis test and find the P-value. (To show your work: Writedown which calculator you are using and what values you are entering into thecalculator.)d. Is there strong evidence that the mean body temperature is different than 98.6degrees? Briefly explain how you know.
- please check this. The recidivism rate for convicted sex offenders is 14%. A warden suspects that this percent is different if the sex offender is also a drug addict. Of the 324 convicted sex offenders who were also drug addicts, 32 of them became repeat offenders. What can be concluded at the αα = 0.05 level of significance? For this study, we should use The null and alternative hypotheses would be: Ho: (please enter a decimal) H1: (Please enter a decimal) The test statistic = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is αα Based on this, we should the null hypothesis. Thus, the final conclusion is that ... The data suggest the populaton proportion is significantly different from 14% at αα = 0.05, so there is statistically significant evidence to conclude that the population proportion of convicted sex offender drug addicts who become repeat offenders…A large cookie company claims the average amount of sodium per cookie is 200 mg. You suspect that the sodium content is different than that, so you take a random sample of 36 cookies and research the nutritional content. You then conduct a hypothesis test that u = 200 vs. the alternative that u + 200. (a) The standardized test statistic for your sample is 2.7. The P-value would then be: A) 0.9965 B) 0.4983 C) 0.0070 D) 0.0035 Selection: (b) Which would be the correct decision for your hypothesis test? A) Reject Ho B) Do not reject Ho Selection: (C) A Type I Error in this situation would be: A) Concluding that p 200 when in fact u = 200 is true. B) Concluding that u = 200 when in fact p 200 is true. C) Concluding that u = 200 when in fact p = 200 is true. D) Concluding that u 200 when in fact u 200 is true. %3DOnly about 15% of all people can wiggle their ears. Is this percent different for millionaires? Of the 398 millionaires surveyed, 40 could wiggle their ears. What can be concluded at the αα = 0.05 level of significance? For this study, we should use Select an answer t-test for a population mean z-test for a population proportion The null and alternative hypotheses would be: H0:H0: ? μ p Select an answer > < ≠ = (please enter a decimal) H1:H1: ? μ p Select an answer < = ≠ > (Please enter a decimal) The test statistic ? z t = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 3 decimal places.) The p-value is ? ≤ > αα Based on this, we should Select an answer fail to reject accept reject the null hypothesis. Thus, the final conclusion is that ... The data suggest the population proportion is not significantly different from 15% at αα = 0.05, so there is statistically insignificant evidence to conclude that the…
- A manufacturer of chocolate chips would like to know whether its bag filling machine works correctly at the 418 gram setting. Is there sufficient evidence at the 0.05 level that the bags are underfilled or overfilled? Assume the population is normally distributed. State the null and alternative hypotheses for the above scenario. H0: Ha:Women athletes at a certain university have a long-term graduation rate of 67%. Over the past several years, a random sample of 38 women athletes at the school showed that 21 eventually graduated. Does this indicate that the population proportion of women athletes who graduate from the university is now less than 67%? Use a 1% level of significance. State the null and alternate hypotheses. H0: p = 0.67; H1: p < 0.67 H0: p = 0.67; H1: p > 0.67 H0: p = 0.67; H1: p ≠ 0.67 H0: p < 0.67; H1: p = 0.67 What sampling distribution will you use? The standard normal, since np < 5 and nq < 5. The Student's t, since np > 5 and nq > 5. The standard normal, since np > 5 and nq > 5. The Student's t, since np < 5 and nq < 5. What is the value of the sample test statistic? (Round your answer to two decimal places.) Find the P-value of the test statistic. (Round your answer to four decimal places.) Based on your answers in parts (a) to…