Test the claim that the mean GPA of night students islarger than 2.5 at the 0.02 significance level.The null and alternative hypotheses would be:Но: и — 2.5 Но: иH1: µ + 2.5 H1:µ > 2.5 H1:p < 0.625—D 2.5 Но:р —D 0.625Но: р — —0.625 Но: р0.625 Но: ш — 2.5Hi:р > 0.625 Нi:р 20.625 Hі:и < 2.5The test is:two-tailed left-tailed right-tailedBased on a sample of 40 people, the sample mean GPAwas 2.54 with a standard deviation of 0.08The p-value is:(to 3decimals)The significance level is:(to 2 decimals)Based on this we:Fail to reject the null hypothesisReject the null hypothesis

Givensample size(n)=40Mean(x)=2.54standard deviation(s)=0.08α=0.02claim is the mean GPA of night…

Answered: Test the claim that the mean GPA of…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Test the claim that the mean GPA of night students is smaller than the mean GPA of day students at the 0.01 significance level.The null and alternative hypothesis would be: H0:μN=μDH0:μN=μDH1:μN≠μDH1:μN≠μD H0:pN≥pDH0:pN≥pDH1:pN<pDH1:pN<pD H0:μN≤μDH0:μN≤μDH1:μN>μDH1:μN>μD H0:pN=pDH0:pN=pDH1:pN≠pDH1:pN≠pD H0:μN≥μDH0:μN≥μDH1:μN<μDH1:μN<μD H0:pN≤pDH0:pN≤pDH1:pN>pDH1:pN>pD The test is: left-tailed two-tailed right-tailed The sample consisted of 35 night students, with a sample mean GPA of 2.23 and a standard deviation of 0.05, and 35 day students, with a sample mean GPA of 2.24 and a standard deviation of 0.07.
Approximately 10%10% of Americans are left-handed (we will treat this as a known population parameter). A study on the relationship between handedness and profession found that in a random sample of 105 lawyers, 16 of them were left-handed.1 Test the hypothesis that the proportion of left-handed lawyers differs from the proportion of left-handed Americans. Clearly state the null and alternative hypotheses.Let pp be the proportion of left-handed lawyers. Calculate the test statistic and p-value.Round your answer for the test statistic to two decimal places, and your answer for the p-value to three decimal places.test statistic = Enter your answer; test statisticp-value = Enter your answer; p-value What do we conclude at the 5% significance level? At the 10% significance level? Significance Level Conclusion 5% Choose the answer from the menu; What do we conclude at the 5% significance level?…
Previously, 12.1% of workers had a travel time to work of more than 60 minutes. An urban economist believes that the percentage has increased since then. She randomly selects 80 workers and finds that 18 of them have a travel time to work that is more than 60 minutes. Test the economist's belief at the x = 0.1 level of significance. What are the null and alternative hypotheses? P = 0.121 versus H1: p Ho: p (Type integers or decimals. Do not round.) > 0.121 Because npo (1- Po) = < 10, the normal model may not be used to approximate the P-value. (Round to one decimal place as needed.)
Test the claim that the mean GPA of night students is larger than 2.1 at the 0.01 significance level. The null and alternative hypotheses would be: 0.525 Ho: u = 2.1 Ho: µ = 2.1 Ho:µ = 2.1 Ho:p 0.525 Ho:p 0.525 H:p> 0.525 H1:p+ 2.1 H:µ > 2.1 H:µ < 2.1 H1:p< 0.525 H :p + 0.525 The test is: left-tailed two-tailed right-tailed Based on a sample of 38 people, the sample mean GPA was 2.11 with a standard deviation of 0.2 The p-value is: (to 3 decimals) The significance level is: (to 2 decimals) Based on this we: O Fail to reject the null hypothesis O Reject the null hypothesis Question Help: Message instructor Submit Question N D arch
Test the claim that the proportion of people who own cats is smaller than 60% at the 0.005 significance level.The null and alternative hypothesis would be: H0:μ=0.6H0:μ=0.6H1:μ≠0.6H1:μ≠0.6 H0:p=0.6H0:p=0.6H1:p≠0.6H1:p≠0.6 H0:p≤0.6H0:p≤0.6H1:p>0.6H1:p>0.6 H0:μ≥0.6H0:μ≥0.6H1:μ<0.6H1:μ<0.6 H0:p≥0.6H0:p≥0.6H1:p<0.6H1:p<0.6 H0:μ≤0.6H0:μ≤0.6H1:μ>0.6H1:μ>0.6 The test is: two-tailed right-tailed left-tailed Based on a sample of 200 people, 51% owned catsThe test statistic is: (to 2 decimals)The p-value is: (to 2 decimals)Based on this we: Reject the null hypothesis Fail to reject the null hypothesis
Under what circumstances is a t statistic used instead of a z-score for a hypothesis test? Justin wants to know whether a commonly prescribed drug does improve the attention span of students with attention deficit disorder (ADD). He knows that the mean attention span for students with ADD who are not taking the drug is 2.3 minutes long. His sample of 12 students taking the drug yielded a mean of 4.6 minutes. Justin can find no information regarding σx , so he calculated s2x =1.96. Determine the critical region using a one-tailed test with alpha = .05. Conduct the hypothesis test (Do the math and compare the t-critical and t-obtained values). State your conclusions in terms of H0 (Should you reject the H0 or fail to reject/accept the H0). Based on your analysis, is there a relationship between the drug and attention span?
Consolidated Power, a large electric power utility, has just built a modern nuclear power plant. This plant discharges waste water that is allowed to flow into the Atlantic Ocean. The Environmental Protection Agency (EPA) has ordered that the waste water may not be excessively warm so that thermal pollution of the marine environment near the plant can be avoided. Because of this order, the waste water is allowed to cool in specially constructed ponds and is then released into the ocean. This cooling system works properly if the mean temperature of waste water discharged is 60°F or cooler. Consolidated Power is required to monitor the temperature of the waste water. A sample of 100 temperature readings will be obtained each day, and if the sample results cast a substantial amount of doubt on the hypothesis that the cooling system is working properly (the mean temperature of waste water discharged is 60°F or cooler), then the plant must be shut down and appropriate actions must be taken…
Previously, 10.4% of workers had a travel time to work of more than 60 minutes. An urban economist believes that the percentage has increased since then. She randomly selects 75 workers and finds that 16 of them have a travel time to work that is more than 60 minutes. Test the economist's belief at the a = 0.1 level of significance. What are the null and alternative hypotheses? 0.104 versus H1: p Ho: p P = (Type integers or decimals. Do not round.) > 0.104 %3D Because npo (1- Po) 10, the normal model be used to approximate the P-value. %3D (Round to one decimal place as needed.)
Suppose the national average dollar amount for an automobile insurance claim is $777.86. You work for an agency in Michigan and you are interested in whether or not the state average is less than the national average. The hypotheses for this scenario are as follows: Null Hypothesis: μ ≥ 777.86, Alternative Hypothesis: μ < 777.86. You take a random sample of claims and calculate a p-value of 0.0232 based on the data, what is the appropriate conclusion? Conclude at the 5% level of significance. Question 9 options: 1) The true average claim amount is significantly different from $777.86. 2) The true average claim amount is significantly less than $777.86. 3) The true average claim amount is significantly higher than $777.86. 4) We did not find enough evidence to say the true average claim amount is less than $777.86. 5) The true average claim…
Test the claim that the proportion of men who own cats is smaller than the proportion of women who own cats at the .10 significance level. The null and alternative hypothesis would be: Но: дм — Мр Но: рм — МF Но: рм — Pr Но: рм — рF Но: им — МЕ Но: рм — РF PF Ho:HM = µf Ho:PM = Pf H1: µM + HF H1:µM PF H1:µM > µF H1:PM < PF The test is: left-tailed right-tailed two-tailed Based on a sample of 60 men, 35% owned cats Based on a sample of 40 women, 55% owned cats The test statistic is: (to 2 decimals) The p-value is: (to 2 decimals) Based on this we: Fail to reject the null hypothesis Reject the null hypothesis
Suppose that we have a problem for which the null and alternative hypothesis are given by: H0: μ = 890. H1:μ ≠ 890. Is this a right-tailed test, left-tailed test, or two-tailed test. Find the z value based on a level of significance of α=.09.
Only about 15% of all people can wiggle their ears. Is this percent different for millionaires? Of the 398 millionaires surveyed, 40 could wiggle their ears. What can be concluded at the αα = 0.05 level of significance? For this study, we should use Select an answer t-test for a population mean z-test for a population proportion The null and alternative hypotheses would be: H0:H0: ? μ p Select an answer > < ≠ = (please enter a decimal) H1:H1: ? μ p Select an answer < = ≠ > (Please enter a decimal) The test statistic ? z t = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 3 decimal places.) The p-value is ? ≤ > αα Based on this, we should Select an answer fail to reject accept reject the null hypothesis. Thus, the final conclusion is that ... The data suggest the population proportion is not significantly different from 15% at αα = 0.05, so there is statistically insignificant evidence to conclude that the…

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