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The wavelength of some violet light is 420.0 nm. What is the frequency of this violet light? V = 8-1

The wavelength of some violet light is 420.0 nm. What is the frequency of this violet light? V = 8-1

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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**Question:** The wavelength of some violet light is 420.0 nm. What is the frequency of this violet light? **Answer Box:** - \(\nu =\) _______ s\(^{-1}\) **Explanation:** To find the frequency (\(\nu\)) of light from its wavelength (\(\lambda\)), you can use the formula: \[ \nu = \frac{c}{\lambda} \] Where: - \(\nu\) is the frequency - \(c\) is the speed of light (\(3.00 \times 10^8\) meters per second) - \(\lambda\) is the wavelength in meters For the given wavelength (\(\lambda = 420.0\) nm), you must convert it to meters: \[ 420.0 \text{ nm} = 420.0 \times 10^{-9} \text{ m} \] Then, plug the values into the formula to calculate the frequency. The resultant frequency will be in s\(^{-1}\), also known as Hertz (Hz).
Transcribed Image Text:**Question:** The wavelength of some violet light is 420.0 nm. What is the frequency of this violet light? **Answer Box:** - \(\nu =\) _______ s\(^{-1}\) **Explanation:** To find the frequency (\(\nu\)) of light from its wavelength (\(\lambda\)), you can use the formula: \[ \nu = \frac{c}{\lambda} \] Where: - \(\nu\) is the frequency - \(c\) is the speed of light (\(3.00 \times 10^8\) meters per second) - \(\lambda\) is the wavelength in meters For the given wavelength (\(\lambda = 420.0\) nm), you must convert it to meters: \[ 420.0 \text{ nm} = 420.0 \times 10^{-9} \text{ m} \] Then, plug the values into the formula to calculate the frequency. The resultant frequency will be in s\(^{-1}\), also known as Hertz (Hz).
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