The water table in soil deposit is 2 m below the ground surface. The soil above the water table has dry unit weight of 14.85 kN/m3. The saturated unit weight of the soil is 20.58 kN/m3. Determine the total vertical stress at a point 4.8 m below the ground. CHOICES A. 88.63 kPa B. 89.68 kPa C. 90.45 kPa D. 87.32 kPa

Q: The soil is having a saturated unit weight 18.0 kN/m and dry unit weight of 11 kN/m. The water table…

A: Saturated unit weight of soil = 18KN/m3 Dry unit weight of soil = 11KN/m3 Given two diagrams in Fig…

Q: SITUATION 2: The water table in soil deposit is 1 m below the ground surface. The soil above the…

A:

Q: A clay formation having a depth of 4 m. underlies a sand formation having a depth of 3 m. The dry…

A: Given data :- Dry unit weight of sand = γd= 16.5 kN/m3 Saturated unit weight of clay = 20.4 kN/m3…

Q: 50 and 100 kN/m vertical line loads are applied on the ground surface as shown in the figure.…

A: For, load= 50 kN/m vertical stress = (2Q/Z) (1/[1+(x/z)])2 Q= 50kN/m x= 5m, Z = 30m Therefore,…

Q: Shear stress (KN/m2) q = 50 kN/m: 5= 50 kN/m² (+50, +50) D C M n= 50 kN/m² 29.3 170.7 0; = 150 kN/m²…

A: by the graphical method

Q: For the soil profile given below, calculate the vertical effective stress in kPa at depth Z = 8 m.…

A: Given data in question  Depths Water table at top Dry densities Saturated densities To find out…

Q: For the seepage situation shown below, calculate the effective vertical stress in kPa at point A.…

A: Given data in question  Saturated weigth 2100 kg/m3 Depths Downward seepage condition  To find out…

Q: a) determine the horizontal effective stress at A. (Ans. 53.36 kPa) b) determine the lateral…

A: For first layer,S = 30%Water Content (w) = 40%Specific Gravity of soil (GS) = 2.7For second…

Q: The soil in a deposit underlying an area where a level ground surface exists has a unit weight of 22…

A: Given: Unit Weight of soil = 22 kN/m3, Depth = 5m

Q: • Thickness of sand layer = 6 m (i.e. X = 6 m) • Thickness of gravel layer = 5 m (i.e. Y = 5 m) •…

A:

Q: A soil profile shown has a zone of capillary rise in the sand overlying the clay. In this zone, the…

A:

Q: A circular area having a radius of 4.5 m carries a uniformly distributed load of 125 kPa is applied…

A:

Q: For the soil profile shown in Figure 3. Find the value of the vertical stress change at point A.…

A:

Q: The profile of a soil consists of a soil layer 4.0 meters below the ground surface. The weight of…

A:

Q: Q- 10 m below sea water is the bed of the sea. Take the unit weight of water = 9.81 kN/m². Take the…

A: Given,height of water level=10 mγw=9.81 kN/m3G=2.67Gsea=1.03ID=20%emax=1emin=0.5To…

Q: 2 m 5 m 2 m Silt Clay 3 m A Sand under artesian pressure Bedrock 7. 6 m Soil profile is given in…

A:

Q: Using equation 6.14, determine the vertical stress (Aoz) increase below the center of paded area at…

A: Given Area = 6.35*3.35m^2 Depth 2m,4,6,8,10m q= 225kn/m^2 Calculate stress at different different…

Q: 1. Compute the effective stress at the mid-height the clay layer. a. 80.21 kPa c. 51.30 kPa b. 84.58…

A: All the given data presented in the figure itself below asneed to find The effective stress in the…

Q: 0.4. the sgown soll prome, vertical total and effective stress at points a, b and c. Clay y= 18 kNm…

A:

Q: Continued. A soil profile is shown below. The vertical stress increase at the middle of lean clay…

A: Note:- Hi! Thank you for the question As per the honor code, We’ll answer the first question since…

Q: A granular soil is subjected to a minor principal stress of 200 kN/m2. If the angle of internal…

A:

Q: Question 2 A sand layer is of 5m depth and under it clay layer of 5m depth. Ysaturated sand = 20…

A: Given- Depth=5 m, Unit weight=20 kN/m2,

Q: Calculate the vertical stress at 20 ft depth, given the concentrated load 250 tons, Poisson's ratio…

A:

Q: A soil with a unit weight of 18 kN/m3 is loaded on the ground surface by a uniformly distributed…

A:

Q: The profile of a soil consists of a soil layer 3.8 meters below the ground surface. The weight of…

A:

Q: From the given Figure, determine the following: a. Effective stress at the bottom of the clay b. if…

A: Given: Soil profile Required: Effective stress at bottom of clay For water table up to soil…

Q: Given the figure is the soil layer of a project site. The proposed building will exert a net stress…

A:

Q: What is the equivalent coefficient of permeability (k) for soil layers of k2 and k3? where k2= 1.03…

A:

Q: 4.11 Determine the vertical stress increase, Aoz, at point A with the following values: 91 = 90…

A: Given: Line load 1, q1 = 90 kN/m Line load 2, q2 = 325 kN/m x1 = 4 m x2 = 2.5 m z = 3 m

Q: A saturated site is underlain by a 5m thick layer of clay with undrained strength = 80 kPa, OCR = 2,…

A: The values given in the question are as follows: The thickness of clay layer(hc)=5 m Undrained…

Q: Consider the soil profile shown in the figure below, and an initial groundwater depth of 5 feet…

A: The values and diagram given in the question are as follows: Initial groundwater depth=5 ft (below…

Q: SITUATION 2: The water table in soil deposit is 1 m below the ground surface. The soil above the…

A:

Q: 2 m e = 0.53 Gs = 2.65 A* 4 m Dry Sand B В e = 0.47 Saturated Sand Gs = 2.67 6 m a. Determine the…

A: Note :- as per our guidelines we are supposed to answer first three subparts unless asked any…

Q: Refer to the soil profile shown. Given H1 = 9.89 m., and H2 = 4.4 m. If the ground water table rises…

A:

Q: A clay formation having a depth of 4 m. underlies a sand formation having a depth of 3 m. The dry…

A:

Q: 17. Refer to the soil profile shown. Given H1 = 9.29 m., and H2 = 5.67 m. If the ground water table…

A:

Q: T T Yw =1- m3 Yc = 2.4 m3 (Note T is ton ) H = 0.60 (coefficient of friction between the base and…

A:

Methods to Determine Vertical Stress

The load applied to the soil is transferred to the underground. The presence of water at soil pores and solid grains above the soil are the primary components that are responsible for the effective load transfer. Due to the load acting, the internal component of the soil or the underground formations undergoes deformations or a tectonic shift. The amount of deformation depends upon the amount of load acting on the soil surface, which indeed, depends on the weight of everything present above the soil. Due to this, the underground soil element develops internal stresses which try to resist the tectonic changes.