The voltage across a 2F capacitor is plotted below. What is the (displacement) current through the capacitor at time t = 25 seconds? Also, how much energy is stored in the electric field from to t = -5s t = 30 s
The voltage across a 2F capacitor is plotted below. What is the (displacement) current through the capacitor at time t = 25 seconds? Also, how much energy is stored in the electric field from to t = -5s t = 30 s
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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Question
![The voltage across a 2F capacitor is plotted below. What is the (displacement)
current through the capacitor at time t = 25 seconds? Also, how much energy is
stored in the electric field from
to
t = 30 s
. Select one option each for Current and Energy.
U
0
U
U
4
2F
ve (0)
5-
5
-10
4
t = -5s
C
Voltage Across Capacitor
5
10
15
t
125-1A
=
125=2A
20
I25-1A
125
= -2A
E30 = 10J
E30 = 14J
E30-16J
E30 - 12J
=
25
30
35](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6d711242-a88c-4a58-a190-33258ba50e1c%2F3864a33f-8954-43eb-937e-602d9adf7e61%2Fh2wa8mv_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The voltage across a 2F capacitor is plotted below. What is the (displacement)
current through the capacitor at time t = 25 seconds? Also, how much energy is
stored in the electric field from
to
t = 30 s
. Select one option each for Current and Energy.
U
0
U
U
4
2F
ve (0)
5-
5
-10
4
t = -5s
C
Voltage Across Capacitor
5
10
15
t
125-1A
=
125=2A
20
I25-1A
125
= -2A
E30 = 10J
E30 = 14J
E30-16J
E30 - 12J
=
25
30
35
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