The vapor pressure of ethanol is 54.68 mm Hg at 25 °C. A nonvolatile, nonelectrolyte that dissolves in ethanol is estrogen. Calculate the vapor pressure of the solution at 25 °C when 12.62 grams of estrogen, C18H2402 (272.4 g/mol), are dissolved in 277.8 grams of ethanol.

Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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### Problem Statement

**Objective: Calculating Vapor Pressure of a Solution**

The vapor pressure of **ethanol** is **54.68 mm Hg** at **25 °C**. A nonvolatile, nonelectrolyte that dissolves in ethanol is **estrogen**.

**Task:**
Calculate the vapor pressure of the solution at **25 °C** when **12.62 grams of estrogen** (**C₁₈H₂₄O₂**, molar mass = **272.4 g/mol**), are dissolved in **277.8 grams of ethanol.**

**Data:**
- **ethanol** = **CH₃CH₂OH**
- Molar mass of ethanol = **46.07 g/mol**
- Vapor Pressure (VP) of pure ethanol at 25 °C = **54.68 mm Hg**

**Required Calculation:**

\[ \text{VP(solution)} = \_\_\_\_ \text{ mm Hg} \]

**Answer Entry:**
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### Explanation for Students

To solve this problem, you need to apply the concept of vapor pressure lowering, which is a colligative property. Use the formula that involves the mole fraction of the solvent and the vapor pressure of the pure solvent.

\[ 
P_{solution} = P_{solvent} \cdot X_{solvent} 
\]

Where:
- \( P_{solution} \) is the vapor pressure of the solution
- \( P_{solvent} \) is the vapor pressure of the pure solvent (ethanol here)
- \( X_{solvent} \) is the mole fraction of the solvent (ethanol) in the solution

Steps:
1. Calculate the moles of ethanol and estrogen.
2. Determine the mole fraction of ethanol in the solution.
3. Apply the formula to find the vapor pressure of the solution. 

Remember:
- Moles of a substance = Mass / Molar Mass
- Mole Fraction (X) = Moles of component / Total moles of all components in solution
Transcribed Image Text:### Problem Statement **Objective: Calculating Vapor Pressure of a Solution** The vapor pressure of **ethanol** is **54.68 mm Hg** at **25 °C**. A nonvolatile, nonelectrolyte that dissolves in ethanol is **estrogen**. **Task:** Calculate the vapor pressure of the solution at **25 °C** when **12.62 grams of estrogen** (**C₁₈H₂₄O₂**, molar mass = **272.4 g/mol**), are dissolved in **277.8 grams of ethanol.** **Data:** - **ethanol** = **CH₃CH₂OH** - Molar mass of ethanol = **46.07 g/mol** - Vapor Pressure (VP) of pure ethanol at 25 °C = **54.68 mm Hg** **Required Calculation:** \[ \text{VP(solution)} = \_\_\_\_ \text{ mm Hg} \] **Answer Entry:** - Text box for the answer - **Submit Answer** button - **Try Another Version** button - Notification for remaining attempts (e.g., "10 item attempts remaining") **Navigation Options:** - **Previous** button - **Next** button ### Explanation for Students To solve this problem, you need to apply the concept of vapor pressure lowering, which is a colligative property. Use the formula that involves the mole fraction of the solvent and the vapor pressure of the pure solvent. \[ P_{solution} = P_{solvent} \cdot X_{solvent} \] Where: - \( P_{solution} \) is the vapor pressure of the solution - \( P_{solvent} \) is the vapor pressure of the pure solvent (ethanol here) - \( X_{solvent} \) is the mole fraction of the solvent (ethanol) in the solution Steps: 1. Calculate the moles of ethanol and estrogen. 2. Determine the mole fraction of ethanol in the solution. 3. Apply the formula to find the vapor pressure of the solution. Remember: - Moles of a substance = Mass / Molar Mass - Mole Fraction (X) = Moles of component / Total moles of all components in solution
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