The value obtained for the test statistic, z, in a one-mean z-test is given. Whether the test is two tailed, left tailed, or right tailed is also specified. For part (a) and (b), determine the P-value and decide whether, at the 10% significance level, the data provide sufficient evidence to reject the null hypothesis in favor of the alternative hypothesis. a. The test statistic in a left-tailed test is z= - 1.38. The P-value is 0.084 . (Round to three decimal places as needed.) At the 10% significance level, the data provides sufficient evidence to reject the null hypothesis in favor of the alternative hypothesis because the obtained P-value is less than the significance level. b. The test statistic in a left-tailed test is z= 1.89. The P-value is. (Round to three decimal places as needed.)

The value obtained for the test statistic, z, in a one-mean z-test is given. Whether the test is two tailed, left tailed, or right tailed is also specified. For part (a) and (b), determine the P-value and decide whether, at the 10% significance level, the data provide sufficient evidence to reject the null hypothesis in favor of the alternative hypothesis. a. The test statistic in a left-tailed test is z= - 1.38. The P-value is 0.084 . (Round to three decimal places as needed.) At the 10% significance level, the data provides sufficient evidence to reject the null hypothesis in favor of the alternative hypothesis because the obtained P-value is less than the significance level. b. The test statistic in a left-tailed test is z= 1.89. The P-value is. (Round to three decimal places as needed.)

Name: Y 9.3.65-PQuestion HelpThe value obtained for the test statistic, z,
Uploaded: 2024-03-20T07:07:12.000Z
Channel: Bartleby
Description: Y 9.3.65-PQuestion HelpThe value obtained for the test statistic, z, in a one-mean z-test is given. Whether the test is two tailed, left tailed, or right tailed is also specified. For parts(a) and (b), determine the P-value and decide whether, at th

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

Test the claim that the proportion of men who own cats is smaller than 40% at the .005 significance level. The null and alternative hypothesis would be:
Test the claim that the proportion of people who own cats is smaller than 30% at the 0.025 significance level. The null and alternative hypothesis would be: Ho: p=0.3 Ho: p = 0.3 Ho: p= 0.3 H₁: p 0.3 The p-value is: Ho: p = 0.3 Ho: p = 0.3 H₁: p0.3 H₁:p> 0.3 (to 2 decimals) (to 2 decimals)
Test the claim that the proportion of people who own cats is significantly different than 40% at the 0.2 significance level. The null and alternative hypothesis would be: Ho:p 0.4 Ho: u 2 0.4 Ho:p = 0.4 Ho: p = 0.4 Ho:u 0.4 H1:p 0.4 The test is: two-tailed left-tailed right-tailed Based on a sample of 700 people, 34% owned cats The p-value is: (to 2 decimals) Based on this we: O Fail to reject the null hypothesis O Reject the null hypothesis Question Help: DVideo M hp
Test the claim that the mean GPA of night students is significantly different than 3.3 at the 0.2 significance level. The null and alternative hypothesis would be: Ho:p0.825 H p 3.3 H p 0.825 H p <3.3 H:p 3.3 The test is: right-tailed two-tailed left-tailed Based on a sample of 80 people, the sample mean GPA was 3.33 with a standard deviation of 0.04 The p-value is: (to 2 decimals) Based on this we: Reject the null hypothesis Fail to reject the null hypothesis
Find the p-value that corresponds to the given standard score, and determine whether to reject the null hypothesis at the 0.10 significance level. Is the alternative hypothesis supported? Z= 0.9 for H0: u=136 pounds and Ha: u is not = 136 pounds. The p-value is ?
A one-sided hypothesis test is to be performed with a significance level of 0.05. Suppose that the null hypothesis is false. If a significance level of 0.01 were to be used instead of a significance level of 0.05, which of the following would be true? A B O E Neither the probability of a Type Il error nor the power of the test would change. Both the probability of a Type II error and the power of the test would decrease. Both the probability of a Type Il error and the power of the test would increase. The probability of a Type II error would decrease and the power of the test would increase. The probability of a Type Il error would increase and the power of the test would decrease.
The test statistic of z=1.54 is obtained when testing the claim that p=0.723. a. Identify the hypothesis test as being two-tailed, left-tailed, or right-tailed. b. Find the P-value. c. Using a significance level of a=0.10, should we reject H0 or should we fail to reject H0?
This is the result of Chi Square test between 2 variables: gender and length of service. If the Null Hypothesis is stated as "There is no significant association between gender and length of service", then table above will clearly allow us to conclude that "there is no significant association between gender and length of service". A. True B. False
The value obtained for the test statistic, z, in a one-mean z-test is given. Whether the test is two tailed, left tailed, or right tailed is also specified. For parts (a) and (b), determine the P-value and decide whether, at the 5% significance level, the data provide sufficient evidence to reject the null hypothesis in favor of the alternative hypothesis. a. The test statistic in a right-tailed test is z=2.00. The P-value is . (Round to three decimal places as needed.)
We have given the value obtained for the test statistic, z, in a one-mean z test. We have also specified whether the test is two tailed, left tailed, or right tailed. Determine the P-value in each case and decide whether, at the 5% significance level, the data provide sufficient evidence to reject the null hypothesis in favor of the alternative hypothesis. a. Right tailed test: z= 2.03 b. Left tailed test: z= -1.84 c. Two-tailed test: z= 3.08 Please also give excel command needed to calculate each of the p-values for each of the questions