The unknown solution in test tube #1 plus (NH4)2SO4 gives no reaction. The solution in test tube #1 is poured into test tube #2. The solution in test tube #2 plus (NH4)2C2O4 gives no reaction. The solution in test tube #2 is poured into test tube #3. The solution in test tube #3 plus Na2HPO4 and NaOH gives a white precipitate. The white precipitate in test tube #3 dissolves in HCl; magnesium indicator and NaOH is added until the solution tests basic. A blue gel is observed at the bottom of the test tube after centrifuging. Group of answer choices
Use the following observations and refer to the steps 6 through 9 of the procedure to determine which cations (Ba2+, Ca2+, Mg2+) are present and absent in an unknown solution.
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The unknown solution in test tube #1 plus (NH4)2SO4 gives no reaction.
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The solution in test tube #1 is poured into test tube #2.
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The solution in test tube #2 plus (NH4)2C2O4 gives no reaction.
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The solution in test tube #2 is poured into test tube #3.
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The solution in test tube #3 plus Na2HPO4 and NaOH gives a white precipitate.
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The white precipitate in test tube #3 dissolves in HCl; magnesium indicator and NaOH is added
until the solution tests basic. A blue gel is observed at the bottom of the test tube after centrifuging.
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A white precipitate is formed when Na2HPO4 and NaOH is treated with solution in test tube #3, it indicates that Mg2+ is present. This is further confirmed by dissolving white precipitate in HCl and Mg indicator. On further addition of NaOH and centrifugation, the formation of blue coloured gel conformed the presence of Mg2+ ion.
so just magnesium is present
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