Chemistry & Chemical Reactivity
10th Edition
ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter1: Basic Concepts Of Chemistry
Section: Chapter Questions
Problem 49RGQ: Fluoridation of city water supplies has been practiced in the United States for several decades. It...
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Question
help me with this. thank you.
![L-atm-
4. Starting from the universal gas constant (R = 0.0821 a), determine the volume (in L) occupied by
%3D
mol-K
2.45 moles of an ideal gas at 32.0°C and a pressure of 0.956 atm.
5. Cadmium (Cd) is a heavy.metal which has a leaching rate of about 0.0012 mg/L per year. Consider a lake
which has a volume of 2.25 x 10° L, and initially contains 0.002 kg of Pb. Determine the amount of Pb (in kg)
present in the lake after 5.0 years assuming that there is no evaporation of water from the lake's surface.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F10b0af56-fbca-4976-a6f8-00a6b6529115%2F4bcd60f0-7e02-4799-9bc2-c45ab362392b%2Fv3fjdy_processed.jpeg&w=3840&q=75)
Transcribed Image Text:L-atm-
4. Starting from the universal gas constant (R = 0.0821 a), determine the volume (in L) occupied by
%3D
mol-K
2.45 moles of an ideal gas at 32.0°C and a pressure of 0.956 atm.
5. Cadmium (Cd) is a heavy.metal which has a leaching rate of about 0.0012 mg/L per year. Consider a lake
which has a volume of 2.25 x 10° L, and initially contains 0.002 kg of Pb. Determine the amount of Pb (in kg)
present in the lake after 5.0 years assuming that there is no evaporation of water from the lake's surface.
![Useful conversion factors
1 tbsp = 14.79 mL
%3D
1 Pa = 1 N/m²
%3D
1 dyne = 1.0 × 10-5 N
1 m3 = 1000L
%3D
%3D
K = 273.15 + °C
%3D](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F10b0af56-fbca-4976-a6f8-00a6b6529115%2F4bcd60f0-7e02-4799-9bc2-c45ab362392b%2Fyqv08f8_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Useful conversion factors
1 tbsp = 14.79 mL
%3D
1 Pa = 1 N/m²
%3D
1 dyne = 1.0 × 10-5 N
1 m3 = 1000L
%3D
%3D
K = 273.15 + °C
%3D
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