The uniform probability distribution was determined to be the following. f(x) = 1/30,000 , 0, $200,000 ≤ x ≤ $230,000 elsewhere The graph of this distribution is a rectangle, which has an area equal to the width multiplied by the height. Recall that the height is given in the probability distribution. That is, the height of this rectangle is 1/30,000. The probability statement is P(x < $212,000). Since this distribution is only valid for values of x between $200,000 and $230,000, the rectangle representing this probability will be between 200,000 and 212,000, giving a rectangle width of _______________ Find the area of this rectangle, which will give P(x < $212,000). P(x < $212,000) = width · height = (_____________) (1/30,000)
The uniform
f(x) = 1/30,000 , 0, $200,000 ≤ x ≤ $230,000 elsewhere
The graph of this distribution is a rectangle, which has an area equal to the width multiplied by the height. Recall that the height is given in the probability distribution. That is, the height of this rectangle is 1/30,000.
The probability statement is P(x < $212,000). Since this distribution is only valid for values of x between $200,000 and $230,000, the rectangle representing this probability will be between 200,000 and 212,000, giving a rectangle width of _______________
Find the area of this rectangle, which will give P(x < $212,000).
P(x < $212,000) = width · height
= (_____________) (1/30,000)
Trending now
This is a popular solution!
Step by step
Solved in 4 steps with 1 images
