**Survey Analysis on Dining Frequency**A survey was conducted with 863 participants to determine how many times per week they dine out at a restaurant. A probability distribution was constructed to represent the results. Let $ X $ be the number of times per week a person dines out, selected randomly from this population. The probability distribution is as follows:\[\begin{array}{|c|c|c|c|c|c|c|c|c|}\hlineX & 0 & 1 & 2 & 3 & 4 & 5 & 6 & 7 \\\hlineP(X) & 0.165 & 0.301 & 0.273 & 0.131 & 0.070 & 0.031 & 0.024 & 0.005 \\\hline\end{array}\]**Tasks:**a. **Compute the Mean $\mu_X$:** - Do not round the final result. - Formula for mean: $\mu_X = \sum [X \cdot P(X)]$b. **Compute the Standard Deviation $\sigma_X$:** - Round the final answer to two decimal places if needed. - Do not round intermediate computations. - Formula for standard deviation: $\sigma_X = \sqrt{\sum [(X - \mu_X)^2 \cdot P(X)]}$

Answered: Image /qna-images/answer/0737e5e0-44d5-4d76-b980-a35cb02601ab.jpg

Answered: A survey asked 863 people how many…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Find the probability distribution for the random variable There is a package containing 16 resistors, of which 12 ard good and 4 are defective. We select a group of 3 of the resistors at random. The random variable X represents the number of defective resistors selected. Find the probability distribution for X. Also sketch a graph of the histogram representing this probability distribution.
On a popular app, users rate hair salons as 1, 2, 3, 4, or 5 stars. Suppose a rating is randomly selected from all the ratings on the app. Let X be the number of stars of the selected rating. Here is the probability distribution of X. ck fn Value x of X esc sign. Check P(X=x) 0.25 0.19 0.09 0.21 0.26 For parts (a) and (b) below, find the probability that the randomly selected hair salon rating has the described number of stars. (a) 3 or more: (b) Fewer than 4:0 Ⓡ ntertained Type here to search. ! 7 ? Q A 1 H hp @ Z 2 3 2 W S # 3 x S alt 4 E D $ 4 5 C O B R % LI F 5 X V to 49 T G 6 5 & Y B 99+ 7 H a hp 4+ N 8 Save For Later © 2023 McGraw Hill LLC. All Rights Reserved. Terms of Use Bigh Center & 100 S 19 144 9 M 105 1 > 4 O 1 1 UDOL JKLE 5- tva P { alt + C ? = 7 insert Submit Assignment * } 1 Am QU ortsc E ← pause ▸ ctri 9 9:19 PM 2/21/2023 backspace USE YOUR SMARTPHONE FOR Reviews Videos Feature Specs Support SCA
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Find the indicated probability and interpret the result. From 1975 through 2020, the mean annual gain of the Dow Jones Industrial Average was 651. A random sample of 31 years is selected from this population. What is the probability that the mean gain for the sample was between 500 and 800? Assume σ=1540.
Suppose you choose four people at random from a Statistics class in which you know 20% of the students have an A average. Let X be the number of students in your sample who have an A average. Obtain the probability distribution for X and plot the probability histogram. X Probability 0 i N 3 A 0.45 0.4 0.35 0.3 i Probability histogram: 0.25 i MI 0.2 0.15- 0.1 0.05- 0 0 1 2 X Figure 1. 3 0.45 0.4 0.35 0.3 0.25 m 10 el 02 0.15 0.1 0.05 0 0 2 X Figure 2. 3 0.45 0.4 0.35- 0.3- 0.25 02- 0.15 0.1- 0.05 0 0 1 2 X Figure 3. 3
Let X = {Email, In Person, Instant Message, Text Message}; P(Email) = 0.06 P(In Person) = 0.55 P(Instant Message) = 0.24 P(Text Message) = 0.15 Is this model a probability distribution? A. Yes. B. No. C. Maybe.
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Groups of adults are randomly selected and arranged in groups of three. The random variable x is the number in the group who say that they would feel comfortable in a self-driving vehicle. Determine whether a probability distribution is given. If a probability distribution is given, find its mean and standard deviation. If a probability distribution is not given, identify the requirements that are not satisfied. OA. H= O B. The table does not show a probability distribution. X P(x) 0 0.368 0.435 0.171 0.026 adult(s) (Round to one decimal place as needed.) 1 Does the table show a probability distribution? Select all that apply. A. Yes, the table shows a probability distribution. B. No, not every probability is between 0 and 1 inclusive. C. No, the sum of all the probabilities is not equal to 1. D. No, the random variable x's number values are not associated with probabilities. E. No, the random variable x is categorical instead of numerical. Find the mean of the random variable x.…
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A survey of almost 44,000 two-child families yielded the accompanying table. The probability distribution of x, the number of boys in a two-child family is given below. Find E(x) and give a practical interpretation of its value. Gender Configuration Proportion D Girl-girl (GG) Boy-girl (BG) Girl-Boy (GB) 0.215 0.267 0.256 P(x) 0.215 0.523 0.262 Boy-boy (BB) 0.262 Choose the correct answer below and fill in the answer box to complete your choice. (Round to three decimal places as needed.) O A. If a very large number of households were sampled, on average, there would be E(x) = boys. O B. If a very large number of two-child households were sampled, on average, there would be E(x) = boys. of getting a family with a boy. %3D O C. If a very large number of two-child households were sampled, there would be a probability of E(x) = O D. In the sample of 44,000 households, each household had E(x) = boys.

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