Answered: The two plates of a parallel -plate… | bartleby

Related questions

Question

The two plates of a parallel -plate capacitor are separated by a distance 8.4mm (assume that the lower plate is at the origin). Lower plate is maintained at potential 7.3V and the upper
plate at 2.0V. Assuming negligible fringing effect at the edges, determine the potential 6.72mm.
O 0.190
O -0.505
O 0.695
O -0.631
O-6.625

Expert Solution

Step by step

Solved in 3 steps with 5 images

SEE SOLUTION Check out a sample Q&A here

Blurred answer

Similar questions

A parallel-plate capacitor with plates of area 500 cm² is charged to an electric potential difference, AV, and then disconnected from the voltage source. (a) Determine an expression for the original electric potential difference, AV, in terms of the capacitor variables (Q, d, A). When the plates are moved a distance D = 0.4 cm farther apart, the voltage on the plates increases by 100 volts. (b) Determine an expression for the new electric potential difference in terms of the new capacitor variables. (c) What is the charge Q on the positive plate of the capacitor? (d) By how much does the energy stored in the capacitor increase due to the movement of the plates?
Two very large metal plates are separated by a distance 0.6 m and charged positive and negative as shown. A gun fires a proton through a hole in the negative plate, and we find that the proton barely reaches point A exactly halfway between the plates before it ィ4 stops and turns around. If the voltage difference between the plates is AValates 9000 V, find the charge density on the positive plate. 0.6 m А) 0.13 х 104 C/m? B) 0.67 x 10-7 C/m2 C) 4.31 x 10-5 C/m2 D) 1.33 x 10-7 C/m2 E) 9.85 x 103 C/m2 O A
Two capacitors C1 = 2.2 ?F and C2 = 1.2 ?F, and are connected in parallel to a 24V source as shown in Fig. a. After they are charged they are disconnected from the source and from each other, and then reconnected directly to each other with plates of opposite sign connected together (see Fig. b). Find the charge on each capacitor and the potential across each after equilibrium is established (Fig. c).
A capacitor can be made of two flat parallel conducting plates of the same area, and opposite polarities. A finite separation between the plates creates a potential difference between them. The capacitance of such a capacitor would vary ----- directly with the area, inversely with the separation O inversely with the area and the separation O directly with the separation, inversely with the area O none of the given choices O directly with the area and the separation
A point particle with charge q = -200 nC and mass m = 3.0x10-6 g is released from rest at the midpoint of a parallel-plate capacitor. The capacitor has plate separation d = 3.0 mm. The negative electrode is at x = 0 and the positive electrode is at x = d. The voltage across the capcitor has been measured to be AVC = 2.5 V. In this problem, ignore the weight of the particle. Give all numerical answers to two significant figures. a) What direction does the particle move? b) What is the electric field strength inside the capacitor, in V/m?
A 5.00 pF, parallel plate, air filled capacitor with circular plates is to be used in a circuit in which it will be subjected to potentials of up to 1.00x102V. The electric field between the plates is to be no greater than 1.00x104 N/C. What must the separation between the plates in the capacitor be? What must the radius of each plate in the designed capacitor be? What is the maximum charge these plates can hold?
Determine the capacitance (PF) of a Teflon-filled parallel-plate capacitor having a plate area of 85cm2 and a plate separation of 0.060 mm. What is the maximum potential difference (kv) that can be applied to a Teflon-filled parallel-plate capacitor having a plate area of 1.85 cm2and a plate separation of 0.060 mm.