Thor is battling the Frost Giants and he uses his hammer, Mjolnir, to zap them with lightning. Thor unleashes a bolt toward the nearest Giant. Mjolnir has an electric potential of zero and the Frost Giant has an electric potential of either +1.9 × 108 V or -1.9 × 108 V (you will decide during part 1 of the question). In order for electricity to conduct through dry air, the electric field between Thor and the Frost Giant must have a magnitude of 3.2 x 106 m' A negatively charged hydroxide ion (OH) in the lightning bolt travels away from Thor. OH ions hold a charge of -1.6 × 10-1⁹ C and they have a mass of 2.82 × 10-26 kg. The OH ion speeds up from rest to a velocity of 6.3 × 105 m.
Thor is battling the Frost Giants and he uses his hammer, Mjolnir, to zap them with lightning. Thor unleashes a bolt toward the nearest Giant. Mjolnir has an electric potential of zero and the Frost Giant has an electric potential of either +1.9 × 108 V or -1.9 × 108 V (you will decide during part 1 of the question). In order for electricity to conduct through dry air, the electric field between Thor and the Frost Giant must have a magnitude of 3.2 x 106 m' A negatively charged hydroxide ion (OH) in the lightning bolt travels away from Thor. OH ions hold a charge of -1.6 × 10-1⁹ C and they have a mass of 2.82 × 10-26 kg. The OH ion speeds up from rest to a velocity of 6.3 × 105 m.
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Question
Assess the following conservation of energy problem. Determine if the answer is correct or incorrect, and explain why
![The Question
Thor is battling the Frost Giants and he uses his hammer, Mjolnir, to zap them with lightning. Thor unleashes a
bolt toward the nearest Giant. Mjolnir has an electric potential of zero and the Frost Giant has an electric
potential of either +1.9 × 108 V or -1.9 × 108 V (you will decide during part 1 of the question). In order for
electricity to conduct through dry air, the electric field between Thor and the Frost Giant must have a magnitude
V
of 3.2 x 106
m
A negatively charged hydroxide ion (OH¯) in the lightning bolt travels away from Thor. OH ions hold a charge
of -1.6 × 10-¹⁹ C and they have a mass of 2.82 × 10-26 kg. The OH-ion speeds up from rest to a velocity of
6.3 × 105 m.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6c806aca-d4f4-488e-823b-e6a92c863c9f%2Fa92a9a0d-8fa3-4bae-a04f-4741813942a5%2Fihgxxof_processed.png&w=3840&q=75)
Transcribed Image Text:The Question
Thor is battling the Frost Giants and he uses his hammer, Mjolnir, to zap them with lightning. Thor unleashes a
bolt toward the nearest Giant. Mjolnir has an electric potential of zero and the Frost Giant has an electric
potential of either +1.9 × 108 V or -1.9 × 108 V (you will decide during part 1 of the question). In order for
electricity to conduct through dry air, the electric field between Thor and the Frost Giant must have a magnitude
V
of 3.2 x 106
m
A negatively charged hydroxide ion (OH¯) in the lightning bolt travels away from Thor. OH ions hold a charge
of -1.6 × 10-¹⁹ C and they have a mass of 2.82 × 10-26 kg. The OH-ion speeds up from rest to a velocity of
6.3 × 105 m.
![3. What is the change in electric potential for the OH ion as it speeds up? Include the correct sign (+) of
this change in potential.
AV =
1
1
qV₁ + = mv² = qVƒ + = mv²
AV =
d =
1
{mv} _{{mv²
q
(2.82 x 10-26 kg) (6.3 × 105 m)
2 * (-1.6 × 10-1⁹ C)
AV = -3.50 × 104 V
4. What distance does the OH ion cover as it speeds up?
d = V² − v ²
2a
Need to find acceleration from Newton's Second Law
F
-
a =
d =
qE
m m
m(v² - v²)
2qE
2
m² - (0)²]
(2.82 × 10-26 kg)[(0)² – (3.5 × 10¹ V)²]
2 * (-1.6 × 10-1⁹ C) * (3.2 × 106
d = 3.37 × 10-5 m](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6c806aca-d4f4-488e-823b-e6a92c863c9f%2Fa92a9a0d-8fa3-4bae-a04f-4741813942a5%2Fi3j6lej_processed.png&w=3840&q=75)
Transcribed Image Text:3. What is the change in electric potential for the OH ion as it speeds up? Include the correct sign (+) of
this change in potential.
AV =
1
1
qV₁ + = mv² = qVƒ + = mv²
AV =
d =
1
{mv} _{{mv²
q
(2.82 x 10-26 kg) (6.3 × 105 m)
2 * (-1.6 × 10-1⁹ C)
AV = -3.50 × 104 V
4. What distance does the OH ion cover as it speeds up?
d = V² − v ²
2a
Need to find acceleration from Newton's Second Law
F
-
a =
d =
qE
m m
m(v² - v²)
2qE
2
m² - (0)²]
(2.82 × 10-26 kg)[(0)² – (3.5 × 10¹ V)²]
2 * (-1.6 × 10-1⁹ C) * (3.2 × 106
d = 3.37 × 10-5 m
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