A point particle with charge q = -200 nC and mass m = 3.0×10-6 g is released from rest at the midpoint of a parallel-plate capacitor. The capacitor has plate separation d = 3.0 mm. The negative electrode is at x = 0 and the positive electrode is at x = d. The voltage across the capcitor has been measured to be AVC = 2.5 V. In this problem, ignore the weight of the particle. Give all numerical answers to two significant figures. a) What direction does the particle move? b) What is the electric field strength inside the capacitor, in V/m?

A point particle with charge q = -200 nC and mass m = 3.0×10-6 g is released from rest at the midpoint of a parallel-plate capacitor. The capacitor has plate separation d = 3.0 mm. The negative electrode is at x = 0 and the positive electrode is at x = d. The voltage across the capcitor has been measured to be AVC = 2.5 V. In this problem, ignore the weight of the particle. Give all numerical answers to two significant figures. a) What direction does the particle move? b) What is the electric field strength inside the capacitor, in V/m?

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Related questions

Q: Problem 6: A parallel-plate capacitor of capacitance C and distance d between plates is fully…

A: Note:- Since you have posted a question with multiple sub-parts, we will solve first three subparts…

Q: Consider two capacitors. One is air-filled, consisting of two parallel plates a = 0.6 cm on a side,…

A: The capacitance of a parallel plate capacitor filled with medium of permittivity ε is given by,…

Q: Find the voltage V across the capacitor and the charge Qf stored by it after the dielectric is…

A: Voltage, V across the capacitor= 2.07 V

Q: A capacitor consists of two large flat parallel plates. One plate has surface charge density 4.96…

A: Given data:- Surface charge density sigma = 4.96 nC/m2 or sigma = 4.96×10-9 C/m2…

Q: A capacitor consists of two large flat parallel plates. One plate has surface charge density 8.79…

Q: A parallel plate capacitor with capacitance C=0.6 mF is connected and charged to a battery with…

Q: An air-filled (empty) parallel-plate capacitor is made from two square plates that are 28 cm on each…

Q: The plates of a spherical capacitor have radii 47.0 mm and 51.6 mm. (a) Calculate the capacitance.…

A: Given Data radii R1 = 47 mm radii R2 = 51.6 mm Formula of capacitance C = 4πε0abb - a

Q: You are asked to construct a capacitor having a capacitance near 1 nF and a breakdown potential in…

A: Given that, Near capacitance, C = 1nF=. Dielectric constant of…

Q: A parallel plate capacitor has a charge on one plate of q = 3.5E-07 C. Each square plate is d1 = 1.7…

Q: A parallel-plate air capacitor has a capacitance of 920 pF. Thecharge on each plate is 3.90 mC. How…

A: Given data C=920 pFQ=3.9 mC

Q: A circular parallel plate capacitor has a separation of 0.050 mm. If the capacitance is 17.3 pF.…

Q: A parallel-plate air capacitor of area A=29 cm2 and plate separation d=2.4 mm is charged by a…

Q: A parallel-plate capacitor in air has a plate separation of 1.38 cm and a plate area of 25.0 cm2.…

Q: A parallel plate capacitor has a capacitance of 2.00 μF and plate separation of 1.60 mm. How…

Q: A parallel-plate capacitor in air has a plate separation of 1.25 cm and a plate area of 25.0 cm².…

A: Here is the explaination in the given image

Q: The plates of a spherical capacitor have radii 55.4 mm and 56.7 mm. (a) Calculate the capacitance.…

A: A spherical capacitor is formed when a sphere either hollow or solid , with radius (r1) is covered…

Q: An initially uncharged air-filled capacitor is connected to a 2.07 V charging source. As a result,…

A: V= 2.07 volts Q= 3.39× 10-5 C K= 4.25

Q: A 70μF capacitor is fully charged by a 15 V battery. iIt is then disconnected from the battery and…

Q: What is the capacitance?

Q: A point particle with charge q = -200 nC and mass m = 3.0x10-6 g is released from rest at the…

A: Given Charge q =-200 nC =- 200 × 10-9 C Mass m = 3× 10-6 g = 3 × 10-9 kg Plate separation d = 3 mm =…

Q: In the figure the battery has a potential difference of V = 10.0 V and the five capacitors each have…

Q: A negatively charged particle of mass 4.30 x 1o-19 kg is moving with a speed of 35.0 m/s when it…

Q: A spherical capacitor consists of an inner sphere radius 0.010 m surrounded by a spherical shell of…

A: Given data: The spherical capacitor consists of an inner sphere of the radius is, r1=0.010 m And…

Q: Two conducting concentric spherical shells have radii a = 0.165 m and b = 0.24 m. Part (a) Express…

A: As per guidelines we can solve only first three subpart.

Q: A certain substance has a dielectric constant of 3.8 and a dielectric strength of 25 MV/m. If it is…

A: Given:- The dielectric constant k = 3.8. The dielectric strength of the substance is 25 MV/m. if…

Concept explainers

Combination of Capacitors

The connection of capacitors can be established in a circuit in two ways.

Question

A point particle with charge q = -200 nC and mass m = 3.0x10-6 g is released from rest at the
midpoint of a parallel-plate capacitor. The capacitor has plate separation d = 3.0 mm. The negative
electrode is at x = 0 and the positive electrode is at x = d. The voltage across the capcitor has been
measured to be AVC = 2.5 V. In this problem, ignore the weight of the particle. Give all numerical
answers to two significant figures.
a) What direction does the particle move?
b) What is the electric field strength inside the capacitor, in V/m?

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1 : Given Values

VIEW

Step 2 : Concepts and Calculations

VIEW

Trending now

This is a popular solution!

Step by step

Solved in 2 steps with 2 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

Similar questions

A capacitor consists of two large flat parallel plates. One plate has surface charge density 4.96 nC/m2 and the other has an equal but opposite surface charge density. The plates are spaced a distance 8.01 cm apart. Give the magnitude of the voltage (difference in electric potential) between the two plates. Answer in units of V.
A slab of copper of thickness b = 1.68 mm is thrust into a parallel-plate capacitor of plate area A = 1.96 cm2 and plate separation d = 5.35 mm, as shown in the figure; the slab is exactly halfway between the plates. (a) What is the capacitance after the slab is introduced? (b) If a charge q = 2.68 µC is maintained on the plates, what is the ratio of the stored energy before to that after the slab is inserted? (c) How much work is done on the slab as it is inserted? (d) Is the slab sucked in or must it be pushed in? Copper (a) Number 4.73e-13 Units (b) Number i 0.686 (c) Number i 5.36e-10 Units J (d) sucked in
A parallel-plate capacitor with a 0.1-mm air gap has a capacitance of 12 µF. (a) When this capacitor is connected to a battery, the maximum magnitude of charge on either plate is 0.18 mC (millicoulomb). What are the magnitude of the electric field between the plates and the energy density (energy per unit volume) in this region? (b) (c) Now suppose this capacitor is disconnected from the battery, and a slab of titanium dioxide (with dielectric constant 100) is inserted between the plates. Indicate whether each of the following quantities increases or decreases after insertion of the dielectric, as well as the factor by which each quantity changes: (i) potential difference across the plates; (ii) capacitance of the capacitor; and (iii) total energy stored in the capacitor. (No calculations are required here.) Calculate the total energy stored in the capacitor with dielectric described in part (b).
Two parallel-plate capacitors, 5.2 uF each, are connected in series to a 11 V battery. One of the capacitors is then squeezed so that its plate separation is halved. Because of the squeezing, (a) how much additional charge is transferred to the capacitors by the battery and (b) what is the increase in the sum of the charges: the charge on the positive plate of one capacitor plus the charge on the positive plate of the other capacitor? Give your answers in Coulombs.
An air-filled parallel-plate capacitor has plates of area 2.10 cm2 separated by 2.10 mm. The capacitor is connected to a(n) 11.0 V battery. (a) Find the value of its capacitance. X PF (b) What is the charge on the capacitor? X pC
The capacity of a battery to deliver charge, and thus power, decreases with temperature. The same is not true of capacitors. For sure starts in cold weather, a truck has a 500 FF capacitor alongside a battery. The capacitor is charged to the full 13.8 VV of the truck's battery. What is the ratio between the energy density per unit mass of the 9.0 kgkg capacitor system and the 130,000 J/kgJ/kg of the truck's battery.
An initially uncharged air-filled capacitor is connected to a 3.29 V charging source. As a result, the capacitor acquires 9.89 x 10- C of charge. Then, while the capacitor remains connected to the charging source, a sheet of dielectric material is inserted between its plates, completely filling the space. The dielectric constant k of this substance is 7.61. Find the voltage V across the capacitor and the charge Qf stored by it after the dielectric is inserted and the circuit has returned to a steady state. V = V Qt = C
A parallel plate capacitor is charged to a potential of 3000 V and then isolated. Find the magnitude of the charge on the positive plate if the plates area is 0.40 m2 and the distance between the plates is 0.020 m. Group of answer choices 68 µC 54 µC 27 µC 18 µC
A parallel-plate capacitor in air has a plate separation of 1.58 cm and a plate area of 25.0 cm2. The plates are charged to a potential difference of 270 V and disconnected from the source. The capacitor is then immersed in distilled water. Assume the liquid is an insulator. (a) Determine the charge on the plates before and after immersion. before pC pC after (b) Determine the capacitance and potential difference after immersion. Cf = F AV = V (c) Determine the change in energy of the capacitor. nJ Need Help? Read It
A parallel plate, air filled capacitor, has plates of area 0.61 m2 and a separation of 0.1 mm.What is its capacitance? (Units: nF=10-9F)