A parallel-plate capacitor in air has a plate separation of 1.58 cm and a plate area of 25.0 cm2. The plates are charged to a potential difference of 270 V and disconnected from the source. Thecapacitor is then immersed in distilled water. Assume the liquid is an insulator.(a) Determine the charge on the plates before and after immersion.beforepCpCafter(b) Determine the capacitance and potential difference after immersion.Cf =FAV =V(c) Determine the change in energy of the capacitor.nJNeed Help?Read It

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