The two angle bars are used to support a tensile load "T". Assume the tensile load to be equally resisted by each angle. 400 mm x 20 mm THK Gusset Plate The steel used is L 6 x 6 x 1. Properties: A = 7096.76 mm² y = 47.244 mm b = 152.4 mm Fy = 248 MPa Fu = 400 MPa Effective hole diameter = 25 mm t = 25.4 mm x = 47.244 mm Use case 2 for shear lag factor. Use NSCP 2015 code. 1. Determine the maximum allowable load that can be carried by the two L6 x 6 x 1 based on yielding of the gross section------ y . b 2. Determine the maximum factored load that can be carried by two L6 x 6 x 1, based on the fracture of the effective net area.----- 3. Determine the maximum allowable tensile load that can be carried.---- 4. Determine the maximum factored tensile load that can be carried------
The two angle bars are used to support a tensile load "T". Assume the tensile load to be equally resisted by each angle. 400 mm x 20 mm THK Gusset Plate The steel used is L 6 x 6 x 1. Properties: A = 7096.76 mm² y = 47.244 mm b = 152.4 mm Fy = 248 MPa Fu = 400 MPa Effective hole diameter = 25 mm t = 25.4 mm x = 47.244 mm Use case 2 for shear lag factor. Use NSCP 2015 code. 1. Determine the maximum allowable load that can be carried by the two L6 x 6 x 1 based on yielding of the gross section------ y . b 2. Determine the maximum factored load that can be carried by two L6 x 6 x 1, based on the fracture of the effective net area.----- 3. Determine the maximum allowable tensile load that can be carried.---- 4. Determine the maximum factored tensile load that can be carried------
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Transcribed Image Text:The two angle bars are used to support a tensile load "T". Assume the tensile load to be equally resisted
by each angle.
400 mm x 20 mm THK
Gusset Plate
The steel used is L 6 x 6 x 1. Properties:
A = 7096.76 mm? y = 47.244 mm
Fy = 248 MPa
Fu = 400 MPa
b = 152.4 mm
b.
t = 25.4 mm
x = 47.244 mm
Effective hole diameter = 25 mm
y
Use case 2 for shear lag factor. Use NSCP 2015 code.
1. Determine the maximum allowable load that can be carried by the two
L6 x 6 x1 based on yielding of the gross section---
2. Determine the maximum factored load that can be carried by two L6 x 6 x 1, based on the fracture of
the effective net area.----
3. Determine the maximum allowable tensile load that can be carried.------
4. Determine the maximum factored tensile load that can be carried--
bo
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