The turbine in the figure uses the flow of the river channeled under the dam, as shown. The friction losses of the system are hf=3.5V^2/(2g), where V is the average velocity in the inlet duct. For what flow in m^3/s would power of 25 MW be extracted? Which of the two solutions has a better "conversion yield"?
The turbine in the figure uses the flow of the river channeled under the dam, as shown. The friction losses of the system are hf=3.5V^2/(2g), where V is the average velocity in the inlet duct. For what flow in m^3/s would power of 25 MW be extracted? Which of the two solutions has a better "conversion yield"?
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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The turbine in the figure uses the flow of the river channeled under the dam, as shown. The friction losses of the system are hf=3.5V^2/(2g), where V is the average velocity in the inlet duct. For what flow in m^3/s would power of 25 MW be extracted? Which of the two solutions has a better "conversion yield"?
![La turbina de la Figura P3.145 utiliza el flujo del río
canalizado bajo la presa, según se muestra. Las pérdidas
del sistema por fricción son h, = 3.5V/(2g), donde V
es la velocidad media en el conducto de entrada. ¿Para
qué caudal en metros cúbicos por segundo se extraerá
una potencia de 25 MW? ¿Cuál de las dos soluciones
tiene un mejor "rendimiento de conversión"?
P3.145
BES
%3D
Z1 = 50 m V
D=4 m
22 = 10 m
23 = 0 m
Turbina](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F54250c85-14dc-400c-ad3b-551675fa5317%2F367a2b43-7360-4766-a1cf-b5880aad33af%2Fh6bho5_processed.jpeg&w=3840&q=75)
Transcribed Image Text:La turbina de la Figura P3.145 utiliza el flujo del río
canalizado bajo la presa, según se muestra. Las pérdidas
del sistema por fricción son h, = 3.5V/(2g), donde V
es la velocidad media en el conducto de entrada. ¿Para
qué caudal en metros cúbicos por segundo se extraerá
una potencia de 25 MW? ¿Cuál de las dos soluciones
tiene un mejor "rendimiento de conversión"?
P3.145
BES
%3D
Z1 = 50 m V
D=4 m
22 = 10 m
23 = 0 m
Turbina
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