The torsional assembly consists of solid 1.5 in. diameter aluminum [G = 4,000 ksi] segments (1) and (3) and a central solid 1.9 in. diameter bronze [G = 6,500 ksi] segment (2). Segment lengths are L1 = L3 = 35 in. and L2 = 64 in. Concentrated torques of TB = 2T0 and TC = T0 are applied to the assembly at B and C, respectively. If the rotation angle at joint B must not exceed 3.8°, determine: (a) the maximum magnitude of T0 that may be applied to the assembly. (b) the maximum shear stress magnitude in aluminum segments (1) and (3). (c) the maximum shear stress magnitude in bronze segment (2).
The torsional assembly consists of solid 1.5 in. diameter aluminum [G = 4,000 ksi] segments (1) and (3) and a central solid 1.9 in. diameter bronze [G = 6,500 ksi] segment (2). Segment lengths are L1 = L3 = 35 in. and L2 = 64 in. Concentrated torques of TB = 2T0 and TC = T0 are applied to the assembly at B and C, respectively. If the rotation angle at joint B must not exceed 3.8°, determine: (a) the maximum magnitude of T0 that may be applied to the assembly. (b) the maximum shear stress magnitude in aluminum segments (1) and (3). (c) the maximum shear stress magnitude in bronze segment (2).
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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The torsional assembly consists of solid 1.5 in. diameter aluminum [G = 4,000 ksi] segments (1) and (3) and a central solid 1.9 in. diameter bronze [G = 6,500 ksi] segment (2). Segment lengths are L1 = L3 = 35 in. and L2 = 64 in. Concentrated torques of TB = 2T0 and TC = T0 are applied to the assembly at B and C, respectively. If the rotation angle at joint B must not exceed 3.8°, determine:
(a) the maximum magnitude of T0 that may be applied to the assembly.
(b) the maximum shear stress magnitude in aluminum segments (1) and (3).
(c) the maximum shear stress magnitude in bronze segment (2).
Transcribed Image Text:Z
A
L₁
B
2To
(2)
C
To
L3
(3)
D
X
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