The torsional assembly consists of solid 1.9 in. diameter aluminum [G= 4,000 ksi] segments (1) and (3) and a central solid 2.3 in. diameter bronze [G= 6,500 ksi] segment (2). Segment lengths are L₁ = L3 = 40 in. and L₂ = 58 in. Concentrated torques of Tg = 2T₁ and Tc = To are applied to the assembly at B and C, respectively. If the rotation angle at joint B must not exceed 2.5°, determine: (a) the maximum magnitude of To that may be applied to the assembly. (b) the maximum shear stress magnitude in aluminum segments (1) and (3). (c) the maximum shear stress magnitude in bronze segment (2). L₁ L2 L3 2To N Answer: (a) To= (b) T1 = T3 = (c) T₂ = A (1) B kip-in ksi ksi (2) ksi C To (3) D X

Structural Analysis
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Chapter2: Loads On Structures
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The torsional assembly consists of solid 1.9 in. diameter aluminum [G = 4,000 ksi] segments (1) and (3) and a central solid 2.3 in.
diameter bronze [G= 6,500 ksi] segment (2). Segment lengths are L₁ = L3 = 40 in. and L₂ = 58 in. Concentrated torques of TB = 2To and
Tc = To are applied to the assembly at B and C, respectively. If the rotation angle at joint B must not exceed 2.5°, determine:
(a) the maximum magnitude of To that may be applied to the assembly.
(b) the maximum shear stress magnitude in aluminum segments (1) and (3).
(c) the maximum shear stress magnitude in bronze segment (2).
y
L₁
L2
2To
L3
A (1)
(2)
N
Answer:
(a) To =
(b) T₁ =
T3 =
(c) T₂ =
B
kip-in
ksi
ksi
ksi
C
To
D
Transcribed Image Text:The torsional assembly consists of solid 1.9 in. diameter aluminum [G = 4,000 ksi] segments (1) and (3) and a central solid 2.3 in. diameter bronze [G= 6,500 ksi] segment (2). Segment lengths are L₁ = L3 = 40 in. and L₂ = 58 in. Concentrated torques of TB = 2To and Tc = To are applied to the assembly at B and C, respectively. If the rotation angle at joint B must not exceed 2.5°, determine: (a) the maximum magnitude of To that may be applied to the assembly. (b) the maximum shear stress magnitude in aluminum segments (1) and (3). (c) the maximum shear stress magnitude in bronze segment (2). y L₁ L2 2To L3 A (1) (2) N Answer: (a) To = (b) T₁ = T3 = (c) T₂ = B kip-in ksi ksi ksi C To D
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