Hours Spent in Child Care5.511.42.111.07.25.19.110.22.98.710.09.09.89.43.18.59.610.67.68.910.76.00.63.79.83.33.55.03.310.37.36.96.14.30.86.98.11.31.69.8 Sample Size40 Hypothesized Mean6 VideoThe time married men with children spend on child care averages 6.0 hours per week (Time, March 12, 2012). You belong to a professional group on family practices that would like todo its own study to determine if the time married men in your area spend on child care per week differs from the reported mean of 6.0 hours per week. A sample of 40 marriedcouples will be used with the data collected showing the hours per week the husband spends on child care. The sample data is contained in the Excel Online file below. Construct aspreadsheet to answer the following questions.XOpen spreadsheeta. What are the hypotheses if your group would like to determine if the population mean number of hours married men are spending in child care differs from the mean reported byTime in your area?Ho : μHa: μ↑66b. What is the sample mean and the p-value?What is the sample mean (to 1 decimal)?hoursCalculate the value of the test statistic (to 2 decimals).What is the p-value (to 4 decimals)? Do not round intermediate calculations.c. Select your own level of significance. What is your conclusion?♥ the null. WeCheck My WorkReset Problemenough evidence to disprove the reported time.

mean x¯=∑xn=26940=6.7 standard deviation s=∑x-x¯2n-1=5.5-6.72+...+9.8-6.7240-1=3.2447

Answered: The time married men with children…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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(d) Identify and interpret a 95% confidence interval for the mean demand and prediction in- terval for an individual demand when x4 = .20, x3 = 6.5, adver = C.
Job sat. Absence Quality Output Week score rate score score 1 3.40 0.05 0.88 8 2 3.60 0.04 0.89 10 3 3.70 0.06 0.90 9 4 3.80 0.03 0.92 10 10 5 3.90 0.04 0.83 8 6 4.20 0.03 0.91 10 7 4.00 0.04 0.92 9 8 4.10 0.05 0.83 9 Weekly goals: Job satisfaction score ≥ 4.50, Absence rate ≤ 0.03, Quality score ≥ 0.95, Output score ≥9 Over the last four weeks, how is the team doing compared to the quality goal?
39.5 44.3 48.5 51.7 59.6 62.8 66.9 71 45.6 46.7 57 46.4 68.2 36.4 54.6 64.4 60.4 51.7 54.8 63.3 58.1 59.2 68.2 56.6 38.6 40 57.4 53.4 54.4 48.3 60.9 46.4 47.4 40 44.7 49.6 59.2 48 65.7 60.1 40 54 52.6 70 53.2 65.7 55.4 60.1 52.8 53 47 46 57.9 48.5 49.1 55.4 63 60.9 51.3 52.8 48 48 71.4 44.3 56.2 47.4 55 44.3 55 46 Report the mean using the rounding rules suggested in the book.mean = median =
A movie studio wishes to determine the relationship between the revenue from rental of DVDS and videotapes of comedies and the revenue generated from the theatrical release of such movies. The studio has the following bivariate data from a sample of fifteen comedies released over the past five years. These data give the revenue x from theatrical release (in millions of dollars) and the revenue y from DVD and videotape rentals (in millions of dollars) for each of the fifteen movies. The data are displayed in the Figure 1 scatter plot. Also given is the product of the theater revenue and the rental revenue for each of the fifteen movies. (These products, written in the column labelled "xy", may aid in calculations.) Theater Rental revenue, x revenue, y ху (in millions of dollars) (in millions of dollars) 14.1 2.6 36.66 25.8 6.7 172.86 18- 7.0 2.6 18.2 16- 27.7 11.7 324.09 14+ 12+ 31.4 5.3 166.42 10+ 49.3 14.9 734.57 36.2 12.5 452.5 20.5 4.7 96.35 65.9 9.3 612.87 60.2 15.7 945.14 10 20 30…
6
15.5, 15.8, 15.9, 15.9, 16.3, 15.4, 16.4, 15.9, 15.5, 16, 16.9, 16.7, 15.3, 16.2, 15.5, 15.8, 16, 16, 15.2, 15.3, 15.5, 15.9, 15.7, 15.3, 16.1, 16.3, 15.3, 17, 17.1, 15.9, 15, 15.9, 15.9, 17.2, 15.5, 15.9, 15.8, 16, 16, 15.7, 16.3, 15.1, 16, 15.8, 16, 16.4, 15.7, 15.8, 16.2, 15.9, 15.7, 16.1, 16.2, 15.9, 16.4, 16, 15.8, 15.5, 16.3, 15.8, 15.1, 16.1, 16.3, 16, 16.1, 16.6, 16.3, 16.3 Perform a hypothesis test using a 1% level of significance to test if the equipment needs to be recalibrated. Step 1: State the null and alternative hypotheses. Ho:o sv 43 Ha:o>v 43 (So we will be performing a right-tailed test.) Part 2 of 4 Step 2: Assuming the null hypothesis is true, determine the features of the distribution of test statistics. Because we are testing the population standard deviation, we will use a x distribution with 67 v degrees of freedom. Part 3 of 4 Step 3: Find the p-value of the test statistic. Sample Mean: = Sample Standard Deviation: s = P(x ?v p-value = Question Help: O Post to…
1. 12 265.2 253.7 2,255.0 132.3 1,295.0 2. 20.2 279.6 286.6 212.8 49.0 466.0 27 311.2 313.8 159.1 6.8 100.3 4 30 328.0 325.9 610.7 4.4 719.0 30 355.0 325.9 610.7 846.8 2,895.9 21.4 281.2 291.4 95.8 104.0 399.5 21.6 292.4 292.2 80.8 0.0 77.2 25.2 292.8 306.6 29.3 190.4 70.3 9 37.2 358.0 354.7 2,863.7 10.9 3,227.8 10 14.4 263.2 263.3 1,435.4 0.0 1,443.0 11 15 272.4 265,7 1,259.3 44.9 828.7 12 22.4 291.2 295.4 33.5 17.6 99.7 13 23.9 299.6 301.4 0.0 3.2 2.5 14 26.6 307.6 312.2 121.3 21.2 41.1 15 30.7 320.4 328.7 757.0 68.9 369.2 Total 10,524.4 1,500.4 12,035.2 The coefficient of determination (r) is The F-ratio is which means that the assessor reject, at the 5% level of significance, the null hypothesis that there is no relationship between the selling price and the area of the house. (Hint: The critical value of Fo5.L13 is 4.67.) Which of the following is an approximate 95% prediction interval for the selling price of a house having an area (size) of 1s (hundred) square feet? O 174.2 to…
A breeder of golden retriever dogs has kept records on litter size for several years. They want to know if litter size is dependent on parent age. Age of Sire 9.0 7.0 6.5 4.3 5.0 4.1 3.7 8.0 7.0 4.1 4.5 7.0 6.0 Age of Dam 2.0 2.5 4.0 3.3 6.0 5.0 4.5 4.1 8.2 2.4 2.9 3.7 4.0 Litter Size 11 10 9 12 5 9 9 8 7 10 12 10 9 a. Perform a correlation analysis. Define your hypothesis, state your conclusions, and show all work.
2. 4.8, 5, 5.2, 5.4,... a. arithmetic, a, = 5.6, a, = 0.2n +4.6 b. geometric, a, = 5.6, a, = 4.6n + 0.2 arithmetic, a, = 5.8, a , = 4.6n +0.2 %3D d. geometric, a, = 5.8, a, = 0.2n +4.6
Consider the following data and 79.4 71.6 95.5 73.0 74.2 81.8 90.6 55.9 75.2 81.9 68.9 74.2 80.7 65.7 67.6 82.9 88.1 77.8 69.4 83.2 82.7 73.8 64.2 63.9 68.3 48.6 83.5 70.8 72.1 71.6 59.4 77.6 a) Organize/Arrange the data in array. Construct a frequency distribution using a class interval of 5.00. Indicate the class boundaries and class limits clearly. (Pt b) Present the frequency distribution by means of a histogram. (
The data of three groups ( X1, X2, X3), each group contains 40 observations are given below. Can you develop a suitable hypothesis for testing the means of the groups X1, X2, and X3. Discuss, and interpret your results? X1 X2 X3 6.8 5.57 3.32 7.89 5.29 7.45 5.29 5.29 7.19 3.46 4.9 7.18 6.08 5 6.54 6.63 4.47 6.1 3.87 3 5.81 4.24 3.46 7.64 6.16 4.9 7.26 3.61 5.74 6.91 5.57 4.69 7.66 5.2 6. 7.51 4.58 6.98 5.39 5.74 7.46 5.39 5.83 7.47 5.39 7.8 6.63 5.66 7.41 4.58 5.29 7.68 5.74 6.63 1
Contact us Search Guides Software Age 1000 9. 1. 991 6. 2. 985 3. 3. 982 3. 4 979 3 976 4. 6. 972 マ 968 4. 964 4. 9 959 Find (i) I; a.9590 b.9760 c. 9640 d. 9850 e. 9790 (ii) d7 a. 30 b.40 C. 60 d. 90 e. 50 8.

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Hours Spent in Child Care
5.5
11.4
2.1
11.0
7.2
5.1
9.1
10.2
2.9
8.7
10.0
9.0
9.8
9.4
3.1
8.5
9.6
10.6
7.6
8.9
10.7
6.0
0.6
3.7
9.8
3.3
3.5
5.0
3.3
10.3
7.3
6.9
6.1
4.3
0.8
6.9
8.1
1.3
1.6

Sample Size	40





Hypothesized Mean	6