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S-adenosyl methionine (SAM-e) is a naturally occurring compound in human cells that is thought to have an effect on depression symptoms. Suppose that a researcher is interested in testing SAM-e on patients who are struggling with cancer. She obtains a sample of n = 20 patients and asks each person to take the suggested dosage each day for 4 weeks. At the end of the 4-week period, each individual takes the Beck Depression Inventory (BDI), which is a 21-item, multiple-choice self-report inventory for measuring the severity of depression. The scores from the sample produced a mean of M = 24.4 with a standard deviation ofs = 6.02. In the general population of cancer patients, the standardized test is known to have a population mean of u = 27.2. Because there are no previous studies using SAM-e with this population, the researcher doesn't know how it will affect these patients; therefore, she uses a two-tailed single-sample t test to test the hypothesis. From the following, select the correct null and alternative hypotheses for this study: O Ho: PSAM-e = 27.2; Hs: PSAMe 27.2 O Ho: MSAMe 2 27.2; Hs: MSAMe> 27.2 O He: PSAM-e S 27.2; H: USAMe> 27.2 O He: PSAM-e 2 27.2; Hs: PSAMe < 27.2 Assume that the depression scores among patients taking SAM-e are normally distributed. You will first need to determine the degrees of freedom. There are v degrees of freedom. Use the t distribution table to find the critical region for a- 0.01. The t Distribution: Proportion in One Tail

S-adenosyl methionine (SAM-e) is a naturally occurring compound in human cells that is thought to have an effect on depression symptoms. Suppose that a researcher is interested in testing SAM-e on patients who are struggling with cancer. She obtains a sample of n = 20 patients and asks each person to take the suggested dosage each day for 4 weeks. At the end of the 4-week period, each individual takes the Beck Depression Inventory (BDI), which is a 21-item, multiple-choice self-report inventory for measuring the severity of depression. The scores from the sample produced a mean of M = 24.4 with a standard deviation ofs = 6.02. In the general population of cancer patients, the standardized test is known to have a population mean of u = 27.2. Because there are no previous studies using SAM-e with this population, the researcher doesn't know how it will affect these patients; therefore, she uses a two-tailed single-sample t test to test the hypothesis. From the following, select the correct null and alternative hypotheses for this study: O Ho: PSAM-e = 27.2; Hs: PSAMe 27.2 O Ho: MSAMe 2 27.2; Hs: MSAMe> 27.2 O He: PSAM-e S 27.2; H: USAMe> 27.2 O He: PSAM-e 2 27.2; Hs: PSAMe < 27.2 Assume that the depression scores among patients taking SAM-e are normally distributed. You will first need to determine the degrees of freedom. There are v degrees of freedom. Use the t distribution table to find the critical region for a- 0.01. The t Distribution: Proportion in One Tail

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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### Two-tailed Hypothesis Testing - Step by Step **Context:** S-adenosyl methionine (SAM-e) is a naturally occurring compound in human cells believed to affect depression symptoms. Suppose a researcher is interested in testing SAM-e on patients struggling with cancer. She obtains a sample of \( n = 20 \) patients and instructs each person to take the suggested dosage daily for 4 weeks. After the 4-week period, each individual takes the Beck Depression Inventory (BDI), a 21-item, multiple-choice self-report inventory that measures depression severity. The scores from the sample produced a mean of \( M = 24.4 \) with a standard deviation of \( s = 6.02 \). In the general population of cancer patients, the standardized test is known to have a population mean of \( μ = 27.2 \). Because there are no previous studies using SAM-e with this population, the researcher does not know how it will affect these patients; she uses a two-tailed single-sample t test to test the hypothesis. **Hypotheses:** From the following, select the correct null and alternative hypotheses for this study: - \( H_0: μ_{\text{SAM-e}} = 27.2; H_1: μ_{\text{SAM-e}} = 27.2 \) - \( H_0: μ_{\text{SAM-e}} \geq 27.2; H_1: μ_{\text{SAM-e}} > 27.2 \) - \( H_0: μ_{\text{SAM-e}} = 27.2; H_1: μ_{\text{SAM-e}} \neq 27.2 \) - \( H_0: μ_{\text{SAM-e}} \leq 27.2; H_1: μ_{\text{SAM-e}} < 27.2 \) The correct hypothesis is: \( H_0: μ_{\text{SAM-e}} = 27.2; H_1: μ_{\text{SAM-e}} \neq 27.2 \) **Statistical Analysis:** Assume that the depression scores among patients taking SAM-e are normally distributed. You will first need to determine the degrees of freedom. There are ___ degrees of freedom (df). **Critical Region:** Use the t distribution table to find the critical region for α = 0.01.
Transcribed Image Text:### Two-tailed Hypothesis Testing - Step by Step **Context:** S-adenosyl methionine (SAM-e) is a naturally occurring compound in human cells believed to affect depression symptoms. Suppose a researcher is interested in testing SAM-e on patients struggling with cancer. She obtains a sample of \( n = 20 \) patients and instructs each person to take the suggested dosage daily for 4 weeks. After the 4-week period, each individual takes the Beck Depression Inventory (BDI), a 21-item, multiple-choice self-report inventory that measures depression severity. The scores from the sample produced a mean of \( M = 24.4 \) with a standard deviation of \( s = 6.02 \). In the general population of cancer patients, the standardized test is known to have a population mean of \( μ = 27.2 \). Because there are no previous studies using SAM-e with this population, the researcher does not know how it will affect these patients; she uses a two-tailed single-sample t test to test the hypothesis. **Hypotheses:** From the following, select the correct null and alternative hypotheses for this study: - \( H_0: μ_{\text{SAM-e}} = 27.2; H_1: μ_{\text{SAM-e}} = 27.2 \) - \( H_0: μ_{\text{SAM-e}} \geq 27.2; H_1: μ_{\text{SAM-e}} > 27.2 \) - \( H_0: μ_{\text{SAM-e}} = 27.2; H_1: μ_{\text{SAM-e}} \neq 27.2 \) - \( H_0: μ_{\text{SAM-e}} \leq 27.2; H_1: μ_{\text{SAM-e}} < 27.2 \) The correct hypothesis is: \( H_0: μ_{\text{SAM-e}} = 27.2; H_1: μ_{\text{SAM-e}} \neq 27.2 \) **Statistical Analysis:** Assume that the depression scores among patients taking SAM-e are normally distributed. You will first need to determine the degrees of freedom. There are ___ degrees of freedom (df). **Critical Region:** Use the t distribution table to find the critical region for α = 0.01.
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