The three positive charges lie at the vertices of an equilateral triangle, as shown in Figure P24.6. Find the potential in the triangular core. Q d d 2Q Figure P24.6
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- IB 50 V 30 V 10V The figure shows a proton moving through a non-uniform electric field with the trajectory described by the solid black arrow. The equipotential curves are shown as green dashed lines. If the proton's speed at point A is 26000 m/s, then what is the proton's speed at point B in m/s? (Hint: The electric force is a conservative force, so the particle's trajectory is irrelevant). (This problem is similar to prob. 38 in Ch. 28 in Knight 3rd ed.) Submit Answer Tries 0/2A particle carrying charge +g is located on the z axis at z=+d. A particle carrying charge-3g is located on the z axis at z=-7d ▸ Part A ▸ ▸ ▾ ▼ Part B Part C Part D At what location on the yaxis with positive coordinate is the potential zera? Express your answer in terms of d. y = Submit Part E O yes O no ROBERSY DE ΓΙ ΑΣΦ 5 Submit Request Answer Are there any locations on the zor y axis where the electrostatic potential is zero for the case where the object at z= 7d carries charge +37 Provide Feedback Ĉ Request Answer ? Next >Three identical point charges each of charge q are located at the ver- tices of an equilateral triangle as in Figure P16.16. The distance from the center of the triangle to each vertex is a. (a) Show that the electric field at the center of the triangle is zero. (b) Find a symbolic expression for the electric potential at the center of the triangle. (c) Give a physical explanation of the fact that the electric b. Figure P16.16 potential is not zero, yet the electric field is zero at the center.
- 21 (27). The lead wire bent in a semicircular shape is uniformly charged S with propaganda charge density, as shown in Figure P24.21. Find the potential at point zero. the table the table 2R 0. R Figure P24.21 2RA solid sphere of radius a=7 cm and dielectric constant ɛ=3.8 has a uniform volume charge Por density of po-29 nC/m2. The electric field is given by E(r) = Poa³ r>a The potential at the center of the sphere is. O a. 45.46 V O b. 60.62 V O c. 6.06 V O d. 30.31 V O e. 15.15 V O f.4.55 VPlease Don't use Al solution