The three-phase full-wave converter shown below is used to rectify the three phase (Y-connection) source signals. The six Thyristor are triggered in the sequence shown. Sketch for firing angle (a=90°) the output voltage (Vo), the phase current, the current for any two Thyristor in any one leg, and the load current (Ia). Then calculate (a) Thyristor average and r.m.s current. (b) Supply average and r.m.s current. (c) The normalized average output voltage. (d) The maximum output voltage. [Vdc = [1 - cos(60+ a)] Vml T If the line-to-neutral voltages are defined as 11 T, T T STA T. Load I sin od sin() ex-> Solve the question sin(with your own hands the corresponding line-to-line voltages are √31% sin (out + ) ---√(4)

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The three-phase full-wave converter shown below is used to rectify the three phase (Y-connection)
source signals. The six Thyristor are triggered in the sequence shown. Sketch for firing angle
(a=90°) the output voltage (Vo), the phase current, the current for any two Thyristor in any one
leg, and the load current (Ia). Then calculate (a) Thyristor average and r.m.s current. (b) Supply
average and r.m.s current. (c) The normalized average output voltage. (d) The maximum output
voltage. [Vdc = [1 - cos(60+ a)]
Vml
T
If the line-to-neutral voltages are defined as
11
T, T
T
STA
T.
Load
I sin od
sin()
ex->
Solve the question
sin(with your own hands
the corresponding line-to-line voltages are
√31% sin (out + )
---√(4)
Transcribed Image Text:The three-phase full-wave converter shown below is used to rectify the three phase (Y-connection) source signals. The six Thyristor are triggered in the sequence shown. Sketch for firing angle (a=90°) the output voltage (Vo), the phase current, the current for any two Thyristor in any one leg, and the load current (Ia). Then calculate (a) Thyristor average and r.m.s current. (b) Supply average and r.m.s current. (c) The normalized average output voltage. (d) The maximum output voltage. [Vdc = [1 - cos(60+ a)] Vml T If the line-to-neutral voltages are defined as 11 T, T T STA T. Load I sin od sin() ex-> Solve the question sin(with your own hands the corresponding line-to-line voltages are √31% sin (out + ) ---√(4)
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