The three forces act on the pipe assembly. If F1 = 50 N and F2 = 80 N, replace this force system by an equivalent resultant force and couple moment acting at O. Express the result in Cartesian vector form. Solution R = -210 k, M = -15 i+ 225 j 180 N 1.25 m 0.5 m F1 0.75 m

Structural Analysis
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ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
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**Problem Statement:**

Three forces act on a pipe assembly:

- \( F_1 = 50 \, \text{N} \)
- \( F_2 = 80 \, \text{N} \)
- Another force of \( 180 \, \text{N} \) is also shown.

**Task:**
Replace these forces with an equivalent resultant force and couple moment about point \( O \). Express the results in Cartesian vector form.

**Solution:**
- Resultant force \( \mathbf{R} = -210 \mathbf{k} \)
- Couple moment \( \mathbf{M} = -15 \mathbf{i} + 225 \mathbf{j} \)

**Diagram Explanation:**

The diagram shows a three-dimensional pipe assembly with forces acting on it. The assembly consists of several straight segments connected at right angles. The configuration includes:

- A vertical force of \( 180 \, \text{N} \) acting downward on a segment aligned parallel to the \( z \)-axis.
- A horizontal force \( F_2 \) of \( 80 \, \text{N} \) acting along the \( y \)-axis.
- A horizontal force \( F_1 \) of \( 50 \, \text{N} \) acting along the \( x \)-axis.

Point \( O \) is marked as the point where the resultant force and couple moment need to be calculated. Distances are marked to help identify the lever arms for calculating moments:

- The distance along the \( y \)-axis to where the \( 180 \, \text{N} \) force acts is \( 1.25 \, \text{m} \).
- The horizontal distance \( 0.5 \, \text{m} \) to the force \( F_2 \).
- The horizontal distance \( 0.75 \, \text{m} \) to the force \( F_1 \).
Transcribed Image Text:**Problem Statement:** Three forces act on a pipe assembly: - \( F_1 = 50 \, \text{N} \) - \( F_2 = 80 \, \text{N} \) - Another force of \( 180 \, \text{N} \) is also shown. **Task:** Replace these forces with an equivalent resultant force and couple moment about point \( O \). Express the results in Cartesian vector form. **Solution:** - Resultant force \( \mathbf{R} = -210 \mathbf{k} \) - Couple moment \( \mathbf{M} = -15 \mathbf{i} + 225 \mathbf{j} \) **Diagram Explanation:** The diagram shows a three-dimensional pipe assembly with forces acting on it. The assembly consists of several straight segments connected at right angles. The configuration includes: - A vertical force of \( 180 \, \text{N} \) acting downward on a segment aligned parallel to the \( z \)-axis. - A horizontal force \( F_2 \) of \( 80 \, \text{N} \) acting along the \( y \)-axis. - A horizontal force \( F_1 \) of \( 50 \, \text{N} \) acting along the \( x \)-axis. Point \( O \) is marked as the point where the resultant force and couple moment need to be calculated. Distances are marked to help identify the lever arms for calculating moments: - The distance along the \( y \)-axis to where the \( 180 \, \text{N} \) force acts is \( 1.25 \, \text{m} \). - The horizontal distance \( 0.5 \, \text{m} \) to the force \( F_2 \). - The horizontal distance \( 0.75 \, \text{m} \) to the force \( F_1 \).
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