The thiourea in a 1.408-g sample of organic material was extracted into a dilute H2SO4 solution and titrated with 37.11 mL of 0.009311 M Hg²+ via the reaction 4(NH2),CS + Hg²+ [(NH2), CS],Hg*+ Find the percentage of (NH2), CS (76.12 g/mol) in the sample. Percentage of (NH2), CS =
The thiourea in a 1.408-g sample of organic material was extracted into a dilute H2SO4 solution and titrated with 37.11 mL of 0.009311 M Hg²+ via the reaction 4(NH2),CS + Hg²+ [(NH2), CS],Hg*+ Find the percentage of (NH2), CS (76.12 g/mol) in the sample. Percentage of (NH2), CS =
Chemistry
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Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![The thiourea in a 1.408-g sample of organic material was extracted into a dilute H₂SO₄ solution and titrated with 37.11 mL of 0.009311 M Hg²⁺ via the reaction
\[ 4(\text{NH}_2)_2 \text{CS} + \text{Hg}^{2+} \rightarrow \left[ (\text{NH}_2)_2 \text{CS} \right]_4 \text{Hg}^{2+} \]
Find the percentage of (\( \text{NH}_2 \))₂ CS (76.12 g/mol) in the sample.
Percentage of (\( \text{NH}_2 \))₂ CS = \_\_\_\_\_\_%](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2bafa3d4-8362-4eaf-b0f1-0c492e72839c%2Fa6ef193e-72af-44a9-bbe1-3013db178198%2Ftmrqe8f_processed.png&w=3840&q=75)
Transcribed Image Text:The thiourea in a 1.408-g sample of organic material was extracted into a dilute H₂SO₄ solution and titrated with 37.11 mL of 0.009311 M Hg²⁺ via the reaction
\[ 4(\text{NH}_2)_2 \text{CS} + \text{Hg}^{2+} \rightarrow \left[ (\text{NH}_2)_2 \text{CS} \right]_4 \text{Hg}^{2+} \]
Find the percentage of (\( \text{NH}_2 \))₂ CS (76.12 g/mol) in the sample.
Percentage of (\( \text{NH}_2 \))₂ CS = \_\_\_\_\_\_%
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