Answered: The test statistic of z = 0.54 is… | bartleby

MATLAB: An Introduction with Applications

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Question

Standard Normal (z) Distribution: Cumulative Area from the LEFT
.00
.01
.02
.03
.04
05
.06
.07
.08
.09
-3.50
and
lower
.0001
-3.4
.0003
.0003
.0003
.0003
.0003
.0003
.0003
.0003
.0003
.0002
-3.3
.0005
.0005
.0005
.0004
.0004
.0004
.0004
.0004
.0004
.0003
-3.2
.0007
0007
.0006
.0006
.0006
.0006
.0006
.0005
.0005
.0005
-3.1
.O010
.0009
.0009
.0009
.0008
.0008
.0008
.0008
.0007
.0007
.0013
.0013
.0012
0012
.0011
.001
.001
-3.0
.o013
.0010
.0010
-2.9
.0019
O018
.0018
.0017
.0016
.0016
.0015
.0015
.0014
.0014
-2.8
.0026
.0025
.0024
.0023
.0023
.0022
.0021
.0021
.0020
.0019
-2.7
.0035
.0034
.0033
.0032
.0031
.0030
.0029
.0028
.0027
.0026
-2.6
.0047
.0045
.0044
.0043
.0041
.0040
.0039
.0038
0037
.0036
-2.5
.0062
.0060
.0059
.0057
.0055
.0054
.0052
.0051
* 0049
.0048
-2.4
.0082
.0080
.0078
.0075
.0073
.0071
.0069
.0068
.0066
.0064
-2.3
.0107
.0104
.0102
.0099
.0096
.0094
.0091
.0089
.0087
.0084
-2.2
.0139
0136
.0132
.0129
.0125
.0122
.0119
.016
0113
O110
-2.1
.0179
0174
.0170
.0166
0162
.0158
.0154
.0150
.0146
.0143
.0202
.0256
-2.0
.0228
.0222
0217
.0212
.0207
.0197
.0192
.0188
.0183
-1.9
.0287
.0281
.0274
.0268
0262
.0250
.0244
.0239
.0233
-1.8
.0359
.0344
.0336
0329
.0322
.0401
.0351
.0314
.0307
.0301
.0294
0436
0427
0418
.0516
-1.7
.0446
.0409
.0392
.0384
.0375
.0367
-1.6
.0548
0537
.0526
0505 * .0495
.0485
.0475
.0465
.0455
-1.5
.0668
.0655
.0643
.0630
.0618
.0606
.0594
.0582
.0571
.0559
-1.4
.0808
.0793
.0778
.0764
.0749
.0735
.0721
.0708
0694
.0681
-1.3
.0968
.0951
.0934
.0918
0901
.0885
.O869
.0853
0838
.0823
-1.2
1151
1131
112
1093
1075
J056
1038
.1020
1003
.0985
-1.1
1357
.1335
1314
1292
1271
1251
.1230
.1210
190
1170
-1.0
.1587
1562
1539
1515
1492
1469
1446
.1423
1401
.1379
1611
-0.9
1841
1814
1788
1762
1736
1711
1685
1660
1635
-0.8
2119
2090
2061
2033
2005
1977
.1949
.1922
1894
1867
-0.7
2420
2389
2358
2327
2296
2266
2236
.2206
2177
2148
-0.6
.2743
2709
2676
2643
2611
2578
2546
.2514
2483
2451
-0.5
.3085
.3050
3015
2981
.2946
.2912
2877
.2843
2810
.2776
-0.4
3446
3409
3372
3336
3300
3264
3228
.3192
3156
3121
-0.3
3821
3783
3745
3707
3669
3632
3594
3557
3520
3483
-0.2
4207
4168
.4129
4090
4052
4013
3974
.3936
.3897
3859
-0.1
.4602
.4562
4522
.4483
.4443
.4404
4364
.4325
4286
4247
-0.0
.5000
4960
.4920
.4880
.4840
.4801
4761
.4721
4681
4641

The test statistic of z = 0.54 is obtained when testing the claim that p > 0.5.
Identify the hypothesis test as being two-tailed, left-tailed, or right-tailed.
Find the P-value.
Using a significance level of a = 0.05, should we reject Ho or should we fail to reject Ho?

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Use the given information to find the P-value. Also, use a 0.05 significance level and state the conclusion about the null hypothesis (reject the null hypothesis or fail to reject the null hypothesis). With H1 : p ≠ 3/5, the test statistic is z = 0.78. Group of answer choices 0.4354; reject the null hypothesis 0.2177; fail to reject the null hypothesis 0.2177; reject the null hypothesis 0.4354; fail to reject the null hypothesis
Use the given information to find the P-value. Also, use a 0.05 significance level and state theconclusion about the null hypothesis (reject the null hypothesis or fail to reject the null hypothesis).With H1: p (does not equal) 3/5, the test statistic is z = 0.78
Test the claim that the mean GPA of night students is significantly different than 2.5 at the 0.1 significance level. The null and alternative hypotheses would be: Ho p=0.625 Hop=2.5 Ho: p=0.625 Ho: : H₁: p > 0.625 The test is: right-tailed left-tailed two-tailed о :p = 0.625 Hoμ = 2.5 H₁ μ = 2.5 o H₁:μ> 2.5 H₁: p < 0.625 H₁: p0.625 H₁: μ2.5 H₁: μ< 2.5 Based on a sample of 35 people, the sample mean GPA was 2.47 with a standard deviation of 0.06 The p-value is: -1.645 The positive significance level is: .10 Based on this we: OTT Reject the null hypothesis Fail to reject the null hypothesis X (to 3 decimals) o(to 2 decimals)
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The test statistic of z = 0.53 is obtained when testing the claim that p > 0.5. Identify the hypothesis test as being two-tailed, left-tailed, or right-tailed. Find the P-value. Using a significance level of α = 0.05, should we reject H0 or should we fail to reject H0?
Use the given information to find the P-value. Also, use a 0.05 significance level and state the conclusion about the null hypothesis (reject the null hypothesis or fail to reject the null hypothesis). The test statistic in a two-tailed test is z=1.95. A. 0.9744; fail to reject the null hypothesis B. 0.0512; fail to reject the null hypothesis C. 0.0512; reject the null hypothesis D. 0.0256; reject the null hypothesis
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Next Question Assume a significance level of a = 0.05 and use the given information to cd d (b) below. Original claim: More than 43% of adults would erase all of their personal information online if they could. The hypothesis test results in a P-value of 0.0443. ..... a. State a conclusion about the null hypothesis. (Reject Ho or fail to reject Ho.) Choose the correct answer below. A. Fail to reject Ho because the P-value is greater than x. B. Reject H, because the P-value is less than or equal to a. C. Fail to reject H, because the P-value is less than or equal to a. O D. Reject Ho because the P-value is greater than a. b. Without using technical terms, state a final conclusion that addresses the original claim. Which of the following is the correct conclusion? A. There is sufficient evidence to support the claim that the percentage of adults that would erase all of their personal information online if they could is more than 43%. B. There is not sufficient evidence to support the…

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