the tee a horizontal distance of 310 m (see photo). The ball leaves the tee at an angle of 45° with respect to the horizontal. If the head of the driver is in contact with the 45-g ball for 1.0 ms, calculate the average force exerted on the ball by the driver. Number Units Leonard Kamsler/Popperfoto/ Getty Images SEN Fa Ma 5

College Physics
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ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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**Problem Statement:**

A professional golfer crushes a golf ball off the tee a horizontal distance of 310 m (see photo). The ball leaves the tee at an angle of 45° with respect to the horizontal. If the head of the driver is in contact with the 45-g ball for 1.0 ms, calculate the average force exerted on the ball by the driver.

**Image Description:**

The image shows a close-up of a golf club about to strike a golf ball, which is placed on a tee. The driver is captured in motion, emphasizing the moment of impact. This visual aids in understanding the context of the problem.

**Solution Input Fields:**

- **Number:** [Input field for entering the numerical answer]
- **Units:** [Input field for specifying the units of the calculated force]

**Explanation:**

To solve this problem, use the formula for average force:

\[ F = \frac{\Delta p}{\Delta t} \]

where \( \Delta p \) is the change in momentum, and \( \Delta t \) is the time duration of contact. To find \( \Delta p \), use the relationship:

\[ \Delta p = m \cdot v \]

where \( m \) is the mass of the golf ball (45 g), and \( v \) is the velocity of the golf ball, which can be calculated using projectile motion formulas given the distance and angle.

This exercise demonstrates the application of physics principles in sports contexts.
Transcribed Image Text:**Problem Statement:** A professional golfer crushes a golf ball off the tee a horizontal distance of 310 m (see photo). The ball leaves the tee at an angle of 45° with respect to the horizontal. If the head of the driver is in contact with the 45-g ball for 1.0 ms, calculate the average force exerted on the ball by the driver. **Image Description:** The image shows a close-up of a golf club about to strike a golf ball, which is placed on a tee. The driver is captured in motion, emphasizing the moment of impact. This visual aids in understanding the context of the problem. **Solution Input Fields:** - **Number:** [Input field for entering the numerical answer] - **Units:** [Input field for specifying the units of the calculated force] **Explanation:** To solve this problem, use the formula for average force: \[ F = \frac{\Delta p}{\Delta t} \] where \( \Delta p \) is the change in momentum, and \( \Delta t \) is the time duration of contact. To find \( \Delta p \), use the relationship: \[ \Delta p = m \cdot v \] where \( m \) is the mass of the golf ball (45 g), and \( v \) is the velocity of the golf ball, which can be calculated using projectile motion formulas given the distance and angle. This exercise demonstrates the application of physics principles in sports contexts.
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