The table shows the number of hospital admissions for Friday the 6th and Friday the 13th. Assume that the two samples are randomly selected. At the 0.05 significance level, test the claim that there is no mean difference in the number of hospital admissions for Friday the 6th and Friday the 13th. (Be sure to subtract in the same direction). Friday 6th Friday 13th Difference 4 2 6 10 5 6 9 13 3 2 11 15 12 12
Is Friday the 13th Unlucky?
The table shows the number of hospital admissions for Friday the 6th and Friday the 13th. Assume that the two samples are randomly selected. At the 0.05 significance level, test the claim that there is no
(Be sure to subtract in the same direction).
| Friday 6th | Friday 13th | Difference |
| 4 | 2 | |
| 6 | 10 | |
| 5 | 6 | |
| 9 | 13 | |
| 3 | 2 | |
| 11 | 15 | |
| 12 | 12 |
What are the correct hypotheses? (Select the correct symbols and values.)
H0: Select an answer μ₁ μ(d) x̄₂ σ₁² x̄₁ s₁² p μ ? = < ≤ ≠ > ≥ Select an answer 0 μ₁ μ₂ x̄₁ p σ₁² s₁² x̄₂ μ
H1: Select an answer x̄₂ μ₁ μ p μ₂ x̄₁ s₂² μ(d) σ₂² ? < ≥ ≠ = ≤ > Select an answer μ x̄₂ s₁² x̄₁ p 0 μ₂ σ₁² μ₁
df =
Based on the hypotheses, find the following:
Test Statistic = (Round to three decimal places.)
Critical value(s) = ±± (Round to three decimal places.)
p-value = (Round to four decimal places.)
Shade the sampling distribution curve with the correct critical value(s) and shade the critical regions. The arrows can only be dragged to t-scores that are accurate to 1 place after the decimal point (these values correspond to the tick marks on the horizontal axis). Select from the drop down menu to shade to the left, to the right, between or left and right of the t-score(s).
Shade: Left of a valueRight of a valueBetween two values2 regions. Click and drag the arrows to adjust the values.
Decision: Select an answer Accept the alternative hypothesis Fail to reject the null hypothesis Reject the null hypothesis Accept the null hypothesis .
Conclusion: Select an answer There is not enough evidence to support There is sufficient evidence to warrant rejection of The sample data supports There is not sufficient evidence to warrant rejection of the claim that there is no mean difference in the number of hospital admissions for Friday the 6th and Friday the 13th.
Trending now
This is a popular solution!
Step by step
Solved in 2 steps with 1 images
