The table below displays the results of a study investigating the effectiveness of bicycle safety helmets in preventing head injury. The data consist of a random sample of 800 bicyclists who were involved in bicycle accidents. Wearing a Helmet Yes No Total Yes 20 220 240 Head Injury No 130 430 560 Total 150 650 800 What is the probability of obtaining a head injury given that the bicyclist was not wearing a helmet? Round to two decimal places.
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- Anyone who has been outdoors on a summer evening has probably heard crickets. Did you know that it is possible to use the cricket as a thermometer? Crickets tend to chirp more frequently as temperatures increase. This phenomenon was studied in detail by George W. Pierce, a physics professor at Harvard. In the following data, x is a random variable representing chirps per second and y is a random variable representing temperature (°F). x 19.8 15.3 20.4 18.1 16.2 15.5 14.7 17.1 y 89.4 73.2 95.3 86.1 78.8 75.2 69.7 82.0 x 15.4 16.2 15.0 17.2 16.0 17.0 14.4 y 69.4 83.3 79.6 82.6 80.6 83.5 76.3 (b) Verify the given sums Σx, Σy, Σx2, Σy2, Σxy, and the value of the sample correlation coefficient r. (Round your value for r to three decimal places.) Σx = Σy = Σx2 = Σy2 = Σxy = r = (c) Find x, and y. Then find the equation of the least-squares line = a + bx. (Round your answers for x and y to two decimal places. Round your answers for a and…The following data represent the number of siblings (brothers and sisters) in the families of 20 students who were surveyed. O siblings = 2, 1 sibling = 3, 2 siblings =7, 3 siblings = 2, 4 siblings = 2. What is the probability of randomly selecting a student with 2 or more siblings? Input three-decimal fraction or percentage. Answer:A psychologist would like to know whether the season (autumn, winter, spring, and summer) has any consistent effect on people's sexual activity. In the middle of each season, a psychologist selects a random sample of 22 students. Each individual is given a sexual activity questionnaire. A one-factor ANOVA was used to analyze these data. Complete the following ANOVA summary table (a = 0.02). Round your answers to three decimal places, if necessary. Source Between Within Total SS 867.72 df MS F 2.98 P-value
- Anyone who has been outdoors on a summer evening has probably heard crickets. Did you know that it is possible to use the cricket as a thermometer? Crickets tend to chirp more frequently as temperatures increase. This phenomenon was studied in detail by George W. Pierce, a physics professor at Harvard. In the following data, x is a random variable representing chirps per second and y is a random variable representing temperature (°F). 21.0 15.1 19.0 17.6 17.5 15.5 14.7 17.1 y 87.8 71.4 94.1 84.7 81.4 75.2 69.7 82.0 15.4 16.2 15.0 17.2 16.0 17.0 14.4 69.4 83.3 79.6 82.6 80.6 83.5 76.3 Find x, and y. Then find the equation of the least-squares line ŷ = a + bx. (Round your answer to four decimal places.) %3D X = y = + %3D Find the value of the coefficient of determination r. What percentage of the variation in y can be explained by the corresponding variation in x and the least-squares line? What percentage is unexplained? (Round your answer for r² to four decimal places. Round your…How much customers buy is a direct result of how much time they spend in the store. A study of average shopping times in a large national houseware store gave the following information (Source: Why We Buy: The Science of Shopping by P. Underhill). Women with female companion: 8.3 min.Women with male companion: 4.5 min. Suppose you want to set up a statistical test to challenge the claim that a woman with a female friend spends an average of 8.3 minutes shopping in such a store. (a) What would you use for the null and alternate hypotheses if you believe the average shopping time is less than 8.3 minutes? Ho: ? = 8.3; H1: ? ≠ 8.3Ho: ? < 8.3; H1: ? = 8.3 Ho: ? = 8.3; H1: ? < 8.3Ho: ? = 8.3; H1: ? > 8.3 Is this a right-tailed, left-tailed, or two-tailed test? right-tailedtwo-tailed left-tailed (b) What would you use for the null and alternate hypotheses if you believe the average shopping time is different from 8.3 minutes? Ho: ? = 8.3; H1: ? > 8.3Ho: ? ≠ 8.3; H1: ? = 8.3…The price of a share of stock divided by the company's estimated future earnings per share is called the P/E ratio. High P/E ratios usually indicate "growth" stocks, or maybe stocks that are simply overpriced. Low P/E ratios indicate "value" stocks or bargain stocks. A random sample of 51 of the largest companies in the United States gave the following P/E ratiost. 9 20 11 35 19 13 15 21 29 53 16 26 21 14 21 27 10 12 47 14 40 18 60 72 33 14 8 49 5 16 8 19 12 31 67 51 26 18 17 20 19 13 25 23 27 44 20 27 19 18 32 (a) Use a calculator with mean and sample standard deviation keys to find the sample mean x and sample standard deviation s. (Round your answers to one decimal place.) (b) Find a 90% confidence interval for the P/E population mean u of all large U.S. companies. (Round your answers to one decimal place.) lower limit upper limit (c) Find a 99% confidence interval for the P/E population mean u of all large U.S. companies. (Round your answers to one decimal place.) lower limit upper…
- (OPHTHALMOLOGY) The following data are from a study on Botox injections. Patients received a high-dose injection in one eye (experimental treatment = treatment E) and a low-dose injection in the other eye (control treatment = treatment C). Patients were asked to rate the level of pain in each eye on a 1–10 scale, with higher scores indicating more pain. The assignment of treatments to eyes was randomized. The subjects came back over several visits. Data from the last visit are given in the following table: 1. Which of the following is the correct test to conduct given the situation above? 2. The hypotheses are: 3. What is the level of significance? 4. What is the computed test statistic? Hint: Use (mean of "Pain in E eye") minus (mean of "Pain in C eye") 5. What is the correct decision based on the p-value or critical value method?Is the difference between the mean annual salaries of statisticians in Region 1 and Region 2 more than $5000? To decide, you select a random sample of statisticians from each region. The results of each survey are shown to the right. At a = 0.10, what should you conclude? Region 1 X1 = $67,700 Region 2 X2 = $62,000 01 = $8825 02 = $9025 n1 = 48 n2 = 43 Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table. ..... Choose the correct null and alternative hypotheses below. B. Ho: H1- H2 O C. Ho: H1 -H2 > 5000 Ha: H1 - H2 55000 O A. Ho: H1 - H2 > 5000 + 5000 Ha: H1 - H2 2 5000 Ha: H1 - H2 = 5000 O E. Ho: H1 - H2 2 5000 O D. Ho: H1 - H2 = 5000 Ha: H1 - H2 # 5000 F. Ho: µ1 - H2 5 5000 Ha: H1 - H2 > 5000 Ha: H1 - H2 В. ZEach year, researchers at the U.S. Bureau of Labor Statistics (BLS) administer the American Time Use Survey (ATUS). Researchers estimate the average amount of time Americans spend on daily activities, such as working, housework, and leisure activities. In particular, one activity that is of interest is the average amount of time Americans spend watching television each day.A researcher complied a random sample of 16 Americans and asked each person how much time they spent watching television each day. The results are given below. 1.9 2.3 3.9 4.4 3.2 1.5 1.2 4.4 0.9 4 0.6 3.9 4.5 1.9 1.8 3.7 Determine the point estimate, x¯ and the sample standard deviation, s. Round the solutions to four decimal places, if necessary.x¯=s=Using a 95% confidence level, determine the margin of error, EE, and a confidence interval for the average time Americans spend watching television each day. Report the confidence interval using interval notation. Round solutions to two decimal places, if…
- answer this in 30 mins. please.. I need the answer right now answer it correctly. Thank you!Is the difference between the mean annual salaries of statisticians in Region 1 and Region 2 more than $4000? To decide, you select a random sample of statisticians from each region. The results of each survey are shown to the right. At a = 0.10, what should you conclude? Region 1 X1 = $67,700 01 = $8875 Region 2 X2 = $61,000 02 = $9250 n1 = 48 n2 = 44 Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table. Choose the correct answer below. O A. Reject Ho. At the 10% significance level, there is sufficient evidence to support the claim that the difference between the mean annual salaries is more than $4000. O B. Fail to reject Ho. At the 10% significance level, there is sufficient evidence to support the claim that the difference between the mean annual salaries is more than $4000. OC. Reject Ho. At the 10% significance level, there is insufficient evidence to support the claim that the difference between…