The system shown in the figure contains gas and is going through two processes: Process 1-2 and Process 2-3. The system starts with P1= 268 kPa and Volume = 0.07 m. Then pressure changes to P2 = 131 KPa. The two processes are as follows: Process 1-2: Adiabatic process and P.V2 Constant. Wghant 29 kJ Process 2-3:Q = 71 k), Wshaft = 0, with the piston fixed (does not move). a) Find the Work during the first process. b) Find the change in the internal energy during each process. Draw the two processes in P-V diagram (on one diagram). 2 1

Elements Of Electromagnetics
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The system shown in the figure contains gas and is going through two processes: Process 1-2 and Process
2-3. The system starts with P1= 268 kPa and Volume = 0.07 m. Then pressure changes to P2 = 131 KPa.
The two processes are as follows:
Process 1-2: Adiabatic process and P.V2 = Constant. Wsran = 29 kJ
Process 2-3:Q = 71 kl, Wshaft = 0, with the piston fixed (does not move).
a)
Find the Work during the first process.
b) Find the change in the internal energy during each process.
Draw the two processes in P-V diagram (on one diagram).
1
2)
Transcribed Image Text:The system shown in the figure contains gas and is going through two processes: Process 1-2 and Process 2-3. The system starts with P1= 268 kPa and Volume = 0.07 m. Then pressure changes to P2 = 131 KPa. The two processes are as follows: Process 1-2: Adiabatic process and P.V2 = Constant. Wsran = 29 kJ Process 2-3:Q = 71 kl, Wshaft = 0, with the piston fixed (does not move). a) Find the Work during the first process. b) Find the change in the internal energy during each process. Draw the two processes in P-V diagram (on one diagram). 1 2)
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