The system of first order differential equations y₁ = -6y₁ + 8y2 + 1 y₂ = 8y1 - 6y2 + 1 where y₁ (0) = 0, y₂ (0) = 0 has solution y₁ (t)= 2 (t) =

Calculus: Early Transcendentals
8th Edition
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Author:James Stewart
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Chapter1: Functions And Models
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Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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The system of first order differential equations
y₁ = -6y₁ + 8y2 + 1
y₂ = 8y16y2 + 1
where y₁ (0) = 0, y₂ (0) = 0
has solution
y₁ (t)=
Y2
y₂
(t) =
Transcribed Image Text:The system of first order differential equations y₁ = -6y₁ + 8y2 + 1 y₂ = 8y16y2 + 1 where y₁ (0) = 0, y₂ (0) = 0 has solution y₁ (t)= Y2 y₂ (t) =
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