The system of first order differential equations y₁ = −4y₁ + 5y2 +1 y2 = 5y₁ - 4y2 +1 where y₁ (0) = 0, y₂ (0) = 0 has solution y₁(t)= 3 t 10/20 5 + 5 -9t t 2 -9t e y2(t) = ²/3e² + 2²/1² 5 - 1 1 5

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Q: The system of first order differential equations y₁ = 5y₁ + 1y2 y2 = −4y₁ + 1y2 where y₁ (0) = 4, y2…

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