The system of first order differential equations has solution y₁ (t) = = y₂ (t) = [3/1₁ 13/12 = - -7 y₁ - 4 y2, 8 y₁ + 5y2, y₁ (0) = = -1 Y2(0) = 8

Calculus: Early Transcendentals
8th Edition
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Author:James Stewart
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Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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The system of first order differential equations
has solution
y₁ (t) =
y₂ (t) =
Sy/₁
13/12
=
-7 y₁ - 4 y2,
8 y₁ + 5y2,
y₁ (0)
Y₂ (0)
= -1
= 8
Transcribed Image Text:The system of first order differential equations has solution y₁ (t) = y₂ (t) = Sy/₁ 13/12 = -7 y₁ - 4 y2, 8 y₁ + 5y2, y₁ (0) Y₂ (0) = -1 = 8
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